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ki77a [65]
3 years ago
11

I don't know if I'm doing this right can someone help me out

Chemistry
1 answer:
Murrr4er [49]3 years ago
4 0
YOUR DOING IT RIGHT CAUSE ITS RIGHT

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Arrange the following H atom electron transitions in order of decreasing wavelength of the photon absorbed or emitted:
Katyanochek1 [597]

The decreasing order of wavelengths of the photons emitted or absorbed by the H atom is : b → c → a → d

Rydberg's formula :

                                   \frac{1}{\lambda} = R_h (\frac{1}{n_1^2}-\frac{1}{n_2^2} ),

where  λ is the wavelength of the photon emitted or absorbed from an H atom electron transition from n_1 to n_2 and R_h = 109677 is the Rydberg Constant. Here n_1 and  n_2 represents the transitions.

(a) n_1 =2 to n_2 = infinity

            \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{\infty^2}  ) = 109677/4     [since 1/infinity = 0] Therefore, \lambda = 4 / 109677 = 0.00003647 m

(b) n_1=4 to  n_2 = 20

           \frac{1}{\lambda} = 109677\times (\frac{1}{4^2}-\frac{1}{20^2}  ) = 6580.62

Therefore,  \lambda = 1 / 6580.62 = 0.000152 m

(c) n_1=3 to  n_2 = 10

          \frac{1}{\lambda} = 109677\times (\frac{1}{3^2}-\frac{1}{10^2}  ) = 11089.56

Therefore,  \lambda = 1 / 11089.56 = 0.00009 m

(d)  n_1=2 to  n_2 = 1

          \frac{1}{\lambda} = 109677\times (\frac{1}{2^2}-\frac{1}{1^2}  ) = - 82257.75

Therefore,  \lambda = 1 /82257.75  = - 0.0000121 m  

[Even though there is a negative sign, the magnitude is only considered because the sign denotes that energy is emitted.]

So the decreasing order of wavelength of the photon absorbed or emitted is b → c → a → d.

Learn more about the Rydberg's formula athttps://brainly.com/question/14649374

#SPJ4

8 0
1 year ago
What mass of K2SO4 would you measure out to prepare 550 ml of a 0.76 M solution
Nikolay [14]
The molecular weight of K2SO4 is 174.26 g/mole. The mass of K2SO4 required to make this solution is calculated in the following way. 
550mL * (0.76mole/1000mL) * (174.26g/mole) = 72.84gram
<span>I hope this helps.</span>
5 0
3 years ago
Read 2 more answers
a = Proton transfer d = SN2 Nucleophilic substitution g = Nucleophilic subs at carbonyl(acyl Xfer) b = Lewis acid/base e= Electr
marissa [1.9K]

Complete Question

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Answer:

The solution to this question is shown on the second uploaded image

Explanation:

4 0
3 years ago
Nature operates the same way everywhere in the universe except where we have evidence
babunello [35]

Answer:

true

Explanation:

5 0
3 years ago
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Which of these solids are most likely amorphous solids? Select all that apply. Rubber sugar plastic candle wax graphite glass.
Ostrovityanka [42]

The solids are characterized as amorphous and crystalline solids based on the arrangement of atoms. The solids that are amorphous are rubber, plastic, candle wax, and glass.

<h3>What are amorphous solids?</h3>

The solids have the arrangement of atoms in the lattice. The solids with an appropriate arrangement of atoms are crystalline solids. For example, sugar, graphite.

The solids with irregular arrangements of atoms in the lattice are amorphous solids. For example, glass, rubber.

Thus, the solids that are amorphous in nature are rubber, plastic, candle wax, and glass.

Learn more about amorphous solids, here:

brainly.com/question/4626187

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2 years ago
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