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coldgirl [10]
3 years ago
9

HELP!!!!!! Stacy finds a gun at a crime scene. Which part of the gun should she never touch?

Chemistry
1 answer:
harkovskaia [24]3 years ago
7 0

Answer:

The trigger

Explanation:

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What are the molarity and the normality of a solution made
Nikitich [7]

Explanation:

It is known that molarity is the number of moles present in a liter of solution.

Mathematically,    Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

Hence, calculate the molarity of given solution as follows.

     Molarity of citric acid = \frac{\text{mass of citric acid}}{\text{molar mass of citric acid}} \times \frac{1}{\text{volume of solution(L)}}

                                 = \frac{25 g}{192.13 g/mol} \times \frac{1}{0.75 L}

                                 = 0.173 M

As citric acid is a triprotic acid so, upon dissociation it gives three hydrogen ions.

          Normality = Molarity × no. of hydrogen or hydroxide ions

                            = 0.173 × 3

                            = 0.519 N

Thus, we can conclude that molarity of given solution is 0.173 and its normality is 0.519 N.

3 0
4 years ago
What causes interstellar dust and clouds of gas to condense into planets and stars?
aleksklad [387]
The gravitational pull
3 0
3 years ago
Which action best demonstrates the transformation of mechanical energy to heat energy?
Marysya12 [62]
I believe the answer is burning a candle
6 0
3 years ago
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At 35 C, a sample of gas has a volume of 256 ml and a pressure of 720.torr. What would the volume
Natalija [7]

Answer: Volume would be 196.15 mL if the temperature were changed to 22^{o}C and the pressure to 1.25 atmospheres.

Explanation:

Given: T_{1} = 35^{o}C = (35 + 273) K = 308 K,     V_{1} = 256 mL,    

P_{1} = 720 torr (1 torr = 0.00131579 atm) = 0.947368 atm

T_{1} = 22^{o}C = (22 + 273) K = 295 K,       P_{2} = 1.25 atm  

Formula used to calculate volume is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{1 atm \times 256 mL}{308 K} = \frac{1.25 atm \times V_{2}}{295 K}\\V_{2} = 196.15 mL

Thus, we can conclude that the volume would be 196.15 mL if the temperature were changed to 22^{o}C and the pressure to 1.25 atmospheres.

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3 years ago
__________ is important to a system because each part of a system relies on the previous work of another part.
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I’m guessing A. Order
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