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Brums [2.3K]
3 years ago
15

What would be the bond order for He 2 2- molecule

Chemistry
1 answer:
LuckyWell [14K]3 years ago
8 0

Answer:

In He2 molecule,

Atomic orbitals available for making Molecular Orbitals are 1s from each Helium. And total number of electrons available are 4.

Molecular Orbitals thus formed are:€1s2€*1s2

It means 2 electrons are in bonding molecular orbitals and 2 are in antibonding molecular orbitals .

Bond Order =Electrons in bonding molecular orbitals - electrons in antibonding molecular orbitals /2

Bond Order =Nb-Na/2

Bond Order =2-2/2=0

Since the bond order is zero so that He2 molecule does not exist.

Explanation:

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What term is defined as splitting large nuclei into smaller ones
svetoff [14.1K]

Answer:

Nuclear Fission.

Explanation:

This happens when a high-energy particle collides with a radioisotope, which splits into 2 daughter nuclei, several neutrons (which can collide with more radioisotopes to cause a chain reaction); and a lot of energy. That's why nuclear power plants are so good.

5 0
3 years ago
Chemistry is defined as:
attashe74 [19]

Answer:

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3 years ago
How much nano3 is needed to prepare 225 ml of a 1.55 m solution of nano3?
andrezito [222]

Answer:

= 29.64 g  NaNO3

Explanation:

Molarity is given by the formula;

Molarity = Moles/Volume in liters

Therefore;

Number of moles = Molarity × Volume in liters

                             = 1.55 M × 0.225 L

                             = 0.34875 moles NaNO3

Thus; 0.34875 moles of NaNO3 is needed equivalent to;

   = 0.34875 moles × 84.99 g/mol

   = 29.64 g

5 0
2 years ago
Look at pic and help
natita [175]

Answer:

Answer

Explanation:

1) Other gasses / or argon (based on what u took in ur school )

2) oxygen

3? Nitrogen

3 0
2 years ago
Read 2 more answers
A hypothetical covalent molecule, X–Y, has a dipole moment of 1.93 1.93 D and a bond length of 109 pm. 109 pm. Calculate the par
Gnesinka [82]

Answer:

q= 110.5 ke

Explanation:

Dipole moment is the product of the separation of the ends of a dipole and the magnitude of the charges.

μ = q * d

μ= Dipole moment (1.93 D)

q= partial charge on each pole

d= separation between the poles(109 pm).

e= electronic charge ( 1.60217662 × 10⁻¹⁹ coulombs)

So,

q= \frac{1.93}{109 * 10^{-12} } coulombs

q = \frac{1.93}{109 * 10^{-12} *  1.60217662 * 10^{-19} } e

q = 1.105 * 10⁵ e

q= 110.5 ke

4 0
3 years ago
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