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Vesna [10]
3 years ago
5

A compound consisting of atoms of large atomic mass is more likely to require:

Chemistry
2 answers:
UkoKoshka [18]3 years ago
8 0
<span>A higher temperature to liquefy</span>
bogdanovich [222]3 years ago
8 0

Answer: Option (a) is the correct answer.

Explanation:

An atom with large atomic mass means it will have more number of electrons and more intermolecular forces of attraction between them. Therefore, in order to liquefy the compound we need to provide kinetic energy to its molecules.

And to provide kinetic energy to more number of electrons we need to heat the compound at high temperature so that intermolecular forces of attraction between large number of atoms can be overcome.

Thus, we can conclude that a compound consisting of atoms of large atomic mass is more likely to require a higher temperature to liquefy.

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How does light pollution affect plants and animals?
swat32

Answer:

sunlight

Explanation:

The plants and animals get confused with the artificial light that is used by the human beings.

8 0
3 years ago
Read 2 more answers
What are the two homologous structures?
photoshop1234 [79]
<span>analogous and <span>homologous</span></span>
4 0
4 years ago
How many grams of molybdenum(Mo) are in 2.68E24 atoms of Mo?
loris [4]
<h3>Answer:</h3>

427 g Mo

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.68E24 atoms Mo or 2.68 × 10²⁴ atoms Mo

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Mo - 95.94 g/mol

<u>Step 3: Convert</u>

<u />2.68 \cdot 10^{24} \ atoms \ Mo(\frac{1 \ mol \ Mo}{6.022 \cdot 10^{23} \ atoms \ Mo} )(\frac{95.94 \ g \ Mo}{1 \ mol \  Mo} ) = 426.966 g Mo

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

426.966 g Mo ≈ 427 g Mo

3 0
3 years ago
What type of property can you observe or measure <br> without chaning the substance
galina1969 [7]
You can observe physical properties using your 5 senses
7 0
3 years ago
Read 2 more answers
Someone please help me!!!!!!!
kirill [66]

this is a lot sorry i can't help

6 0
3 years ago
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