2SO2(g) + O2(g) ---> 2SO3(g)
• 2SO2(g) + O2(g) <--- 2SO3(g)
• 2SO2(g) + O2(g) <---> 2SO3(g)
• 2SO2(g) + O2(g) <--->> 2SO3(g)
• Note: The rate of change reaches an
equilibrium. The concentration of
reactants and products is not equa
Answer: B
Explanation: im pretty sure my teacher mentioned something about N--h bonds are non polar
Answer:
B
Explanation:
The wolf with shorter legs would not be an adaptation but more of a birth defect as a wolf with short legs would be at a disadvantage.
Answer:
= 1.5 eq
Explanation:
One definition of an equivalent weight is that it is mass of a substance that gains or loses 1 mole of electrons.
Al3+ has lost 3 e-, so there are 3 equivalent weights in 1 mol Al3+.
1 mol Al3+ =3 eq. wts.
1 mol Al x(27 g / 1 mol)x(1 mol / 3 eq. wts.) = 9.0 g = 1 eq. wts.
13.5 g Al3 + x (1 eq.wt. / 9.0 g) = 1.5 eq
Hey there!:
is the solution <span>saturated , ie :
</span>They are the ones that have reached the exact solubility coefficient.<span>If we mix 64.4 g of KCl at 200.0 g of water at 20 º C, we'll see that the 32.2 g will dissolve and the remainder (32.2 g) will precipitate, forming the bottom body. In this case we will then have a solution saturated with background. However, if we want only the saturated solution, simply perform a simple filtration to separate the precipitate from the saturated solution.
hope this helps!</span>
