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3 years ago

Dry ice, or solid cabon dioxide, has the molecular formula of CO2. How should you classify it?

1 answer:

6 0

You should classify it as co2 solid as CO2(s) and that small left comes to the bottom right hand side and dry ice is a form of liquid carbon dioxide so u should write it as CO2(l) and that L comes to the bottom right hand sise

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6) A volume of 473 mL of oxygen was collected at 27°C. What volume would the oxygen occupy at

sertanlavr [38]

Answer : The volume of oxygen occupy at 173° would be, 703.2 mL

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=473mL\\T_1=27^oC=(27+273)K=300K\\V_2=?\\T_2=173^oC=(173+273)K=446K$

Now put all the given values in above equation, we get:

$\frac{473mL}{300K}=\frac{V_2}{446K}\\\\V_2=703.2mL$

Therefore, the volume of oxygen occupy at 173° would be, 703.2 mL

6 0

3 years ago

NEED ANSWER, ASP! WILL MARK BRAINLIEST!!

Phoenix [80]

Answer:

Answers are below

Explanation:

1. A

2. B

3. A

4. A

5. A

6. B

7. A

8. B

9. B

10. B

11. A, B

12. A

13. A

14. A,B

15. A

16. Not sure

17. Maybe both not sure

18. A

7 0

3 years ago

Select the letter of a category on which you should focus when proofreading.

oee [108]

B. Who, what, when, where, why, and how. Those are the most important and key componants in a story.

8 0

3 years ago

Using the standard reduction potentials, Pb 2+(aq) + 2e– => Pb(s), E° = –0.13 V Fe 2+(aq) + 2e– => Fe(s), E° = –0.44 V Zn

mojhsa [17]

Answer:

Pb(s), Fe(s) and Zn(s) will reduce $Mn^{3+}$ to $Mn^{2+}$

Fe(s) and Zn(s) will reduce $Cr^{3+}$ to $Cr$

Explanation:

Standard reduction potential denotes ability to consume electrons from another species.

Hence, higher the standard reduction potential, higher will be the ability to oxidize another species.

Metal with $E_{red}^{0}$ value lower than 1.51 V will donate electron to $Mn^{3+}$ and thus reduces $Mn^{3+}$ to $Mn^{2+}$ .

So, Pb(s), Fe(s) and Zn(s) will reduce $Mn^{3+}$ to $Mn^{2+}$ .

Metal with $E_{red}^{0}$ value lower than -0.40 V will donate electron to $Cr^{3+}$ and thus reduces $Cr^{3+}$ to $Cr$ .

So, Fe(s) and Zn(s) will reduce $Cr^{3+}$ to $Cr$ .

6 0

3 years ago

Which of the following is a physical property? A. Flammability B. Heat of combustion C. Solubility D.Toxicity

Rasek [7]

I think it would be solubility but I’m not sure

6 0

3 years ago

Read 2 more answers