<span>we have that
the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]
we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]
z1=3[cos 110° + i sin 110°]
cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]
z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is
</span>z1=3[cos 110° + i sin 110°]<span>
</span>z2=3[cos 230° + i sin 230°]
z3=3[cos 350° + i sin 350°]<span>
</span>
Hey can you take another pic
Answer:
Who is the youngest in your family?
total amount is $46.75 and if they split the cost it is $15.58
Answer:
The coordinates are x = -1 and y = -2.
Step-by-step explanation:
Given:
Equations are 2x-4y=6 and 3x+y=-5.
Now, to find the coordinates.
...........(1)
...........(2)
So, first we solve the equation 1 to get the value of 
.
Subtracting both sides by 
we get:
Dividing both sides by 2 we get:
Now, we put the value of in equation 2 to get 
.
On solving the whole equation we get :
And, now putting the value of in equation (1) we get :
on solving we get:
Therefore, the coordinates are x=-1 and y=-2.
