Answer:
3
Step-by-step explanation:
The answer to the question is x > 16
This shows that x is bigger than 16
Answer:
Kendra should have multiplied the x-values by 75 to get the y-values
Step-by-step explanation:
Given
Table
X|| Y
1 || 75
2 || 150
3 || 225
4 || 300
5 || 375
Given that Kendra multiply x by 7.5 to get y
The relationship of x and y can be calculated as thus;
y = rx
Where y and x are the values at the y and x column respectively and r is the constant of proportionality
When y = 75, x = 1.
Plug in these values in the above formula
y = rx becomes
75 = r * 1
75 = r
r = 75
When y = 150, x = 2
150 = r * 2
Multiply both sides by ½
150 * ½ = r * 2 * ½
75 = r
r = 75
When y = 225, x = 3
225 = r * 3
Multiply both sides by ⅓
225 * ⅓ = r * 3 * ⅓
75 = r
r = 75
Notice that r remains 75 and the difference between y values is 75
If you apply these formula on when y = 300 or 375 and when x = 4 or 5, the constant of proportionality will remain The value of 75.
Hence, Kendra mistake is that; Kendra should have multiplied the x-values by 75 to get the y-values
Yes it is correct. You plotted the slope and initial rate value correctly and found the
point of intersection.
You can download the answer here
bit.
ly/3a8Nt8n
The range of the primary phone data is 0.28.
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.
To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28
To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73
To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12
To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6
The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
