To calculate the value of the half life we proceed as follows;
a/2=ae^(-2.360t)
the a(s) will cancel and we shall remain with:
1/2=e^-2.360t
introducing the natural logs we get:
ln (1/2)=ln e^(-2.360t)
ln(1/2)=-2.360t
hence;
t=(ln 0.5)/(-2.360)
t=0.294
the answer is t=0.294
Answer: no
Step-by-step explanation:
the average is 14.6 miles so statement is correct but its not qualitative
Answer:
8 < x < 40
Step-by-step explanation:
x − 8 must be more than 0, but it can't be greater than 32.
0 < x − 8 < 32
8 < x < 40
A more precise answer would require law of cosines and calculus.
Okie so I can see you tomorrow and I’ll be right there on time to meet
