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Vlad [161]
3 years ago
8

Find the y and x equation of this graph

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
4 0
It equals 45 degrees because if you have a ~ line it means you have 45 degrees and don't forget to thank me
You might be interested in
Which of the following are possible solutions to following system of linear inequalities:
lapo4ka [179]
The answer Is F or the C
5 0
3 years ago
Find the value of (+328.62) – (+98.6). A. 230.02 B. 427.22 C. –427.22 D. –230.02
Jet001 [13]

Answer:

Option A - (+328.62)-(+98.6)=230.02

Step-by-step explanation:

We have given the expression (+328.62)-(+98.6)

We have to find the value of the expression ?

Solution :

Step 1 - Write the expression

=(+328.62)-(+98.6)

Step 2 - Applying symbol rule i.e. multiplication of positive into negative is always negative, (-)(+)=(-)

=328.62-98.6

Step 3 - Solve

=230.02

Therefore, The value of the expression is (+328.62)-(+98.6)=230.02

So, Option A is correct.

7 0
3 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
The measure of the exterior angle of the triangle is
Nookie1986 [14]

Answer:

jsjsjsisusbbdbdjsjcjdjsjjsjsjsjsjdjxjx

4 0
3 years ago
7. A scatter plot was created to show the relationship
Ksju [112]

Answer:

1020 students

Step-by-step explanation:

Given the trend line equation :

y = 0.1x + 18,

where y is the total number of staff members and x is the total number of students.

Using the equation, the predicted number of students in a school with 120 staffs ;

y = 120

y = 0.1x + 18

120 = 0.1x + 18

120 - 18 = 0.1x

102 = 0.1x

x = 102 / 0.1

= 1020 students

7 0
3 years ago
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