All categories

2 years ago

Ryan bought a brand new car for $18,000. Its value depreciated at a rate of 1.2%.

Mathematics

1 answer:

kirza4 [7]2 years ago

6 0

Answer:

A(t)= 18000(0.988)^t

Step-by-step explanation:

Given data

Ryan bought a brand new car for $18,000

Its value depreciated at a rate of 1.2%

Let us use the compound expression

A= P(1-r)^t

substitute

A= 18000(1-0.012)^t

A(t)= 18000(0.988)^t

Hence the expression is A(t)= 18000(0.988)^t

You might be interested in

A lot of points for who gets this right!

tigry1 [53]

Answer:

on the end of the graph (5,10)

Step-by-step explanation:

hope that

5 0

2 years ago

Identify BR rounded to the nearest tenth. HELP PLEASE!!

ahrayia [7]

Answer:

Step-by-step explanation:

Use cosine:

$cosine=\dfrac{adjacent}{hypotenuse}$

We have

$adjacent=42\\hypotenuse=BR\\\alpha=31^o$

$\cos31^o\approx0.8572$

Substitute:

$\dfrac{42}{BR}=0.8572$

$\dfrac{42}{BR}=\dfrac{8,572}{10,000}$ <em>cross multiply</em>

$8,572BR=420,000$ <em>divide both sides by 8,572</em>

$BR=\dfrac{420,000}{8,572}$

$BR\approx49.0$

5 0

2 years ago

Which expressions describe the end behaviors of the function f(x)=2^x+3. modeled by the graph attached to this. Choose all that

Gala2k [10]

As x increases without bound, f(x) also increases without bound

3 0

2 years ago

Cual es la magnitud de la aceleración angular de una llanta de un automóvil que adquiere una velocidad angular de 350 rad/s en 2

drek231 [11]

Respuesta:

175 rad / s²

Explicación paso a paso:

Dado que :

Velocidad angular final = 350 rad / s

Tiempo empleado = 2 segundos

La aceleración angular, a =?

Recordar ; la aceleración angular es igual a la carga en velocidad angular con el tiempo

(velocidad final - Velocidad inicial) / tiempo empleado

Velocidad inicial = 0 rad / s

Aceleración angular = (350 - 0) / 2 = 350/2

= 175 rad / s²

3 0

2 years ago

A= V^2/r <br> Solve the formula for r.

kotegsom [21]

Answer:

$\bold{r=\dfrac{V^2}A}$

Step-by-step explanation:

$\bold{A=\dfrac{V^2}r}\\^{\cdot r}\qquad ^{\cdot r}\\\bold{Ar=V^2}\\ ^{\div A}\quad\ ^{\div A}\\\bold{r=\dfrac{V^2}A}$

7 0

2 years ago