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kvasek [131]
3 years ago
12

Write a verbal statement that represents the expression 4 + k.

Mathematics
2 answers:
jolli1 [7]3 years ago
7 0
The sum of four and a number
Stels [109]3 years ago
7 0

Answer:

The sum of 4 and an integer.

Step-by-step explanation:

To solve this problem we need to transform the expression written in an algebraic form to a verbal statement.

  1. In this expression, first of all we can notice that the operation given is a sum.
  2. One of the numbers is 4 and the other number is represented by the letter k. Since we are not given any conditions on the k, we could say that k is any number (although in math, the k usually represents an integer, so we'll consider k to be an integer).

Thus, 4 + k would be expressed as "the sum of 4 and an integer"

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How do you write 5y<3 without exponents?
satela [25.4K]

Answer:

When an exponent is 1, the base remains the same. a 1 = a . When an exponent is 0, the result of the exponentiation of any base will always be 1, although some debate surrounds 0 0 being 1 or undefined. For many applications, defining 0 0 as 1 is convenient.. a 0 = 1 . Shown below is an example of an argument for a 0 =1 using one of the previously mentioned exponent laws.

Step-by-step explanation:

4 0
2 years ago
Please look at this multiple choice, thanks!
Nastasia [14]

Step-by-step explanation:

\frac{y - y1}{x - x1}  =  \frac{y2 - y1}{x2 - x1}

\frac{y - 0}{x - ( - 1)}  =  \frac{3 - 0}{1 - ( - 1)}

\frac{y}{x + 1}  =  \frac{3}{1 + 1}

\frac{y}{x + 1}  =  \frac{3}{2}

y =  \frac{3}{2} (x + 1)

y =  \frac{3}{2} x +  \frac{3}{2}

option B

7 0
3 years ago
You are creating bracelets and then selling them to your friends at a 85% markup rate. If it costs you $1.80 to create the brace
posledela

Answer:

you will add $1.53 to every bracelet you make

Step-by-step explanation:

figure out what 85 percent of 1.80 is and then add that to 1.80 for the total price

85% x 1.8 = 1.53 (markup ammount)

1.80 + 1.53 = 3.33 (total cost)

5 0
3 years ago
Help math question derivative!
atroni [7]
Let f(x)=\sec^{-1}x. Then \sec f(x)=x, and differentiating both sides with respect to x gives

(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1
f'(x)=\dfrac1{\sec f(x)\tan f(x)}

Now, when x=\sqrt2, you get

(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}

You have \sec^{-1}\sqrt2=\dfrac\pi4, so \sec\left(\sec^{-1}\sqrt2\right)=\sqrt2 and \tan\left(\sec^{-1}\sqrt2\right)=1. So (\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}
5 0
3 years ago
What percent of 200 is 290
GrogVix [38]

\frac{290}{200} * 100 = 1.45 * 100 = 145.

So, Our final answer is 145%
8 0
2 years ago
Read 2 more answers
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