All categories

4 years ago

If a + 1 = b, then b > a.

Mathematics

2 answers:

photoshop1234 [79]4 years ago

8 0

<h2>Answer with explanation:</h2>

When a is positive:

Let us consider a=10

and a+1=b

This implies that:

b=11

As we know that 11>10

Hence, b>a

When a is negative:

Let us consider a= -2

and a+1=b

This implies that:

b= -1 (Since -2+1= -1 )

As we know that -1 > -2

Hence, b>a

No, it is not possible to create a set of values for a and b such that the numerical relationship shown in the given conditional statement is false .

Since as we no that no matter whether a is positive or negative we always have:

a < a+1

Hence, a< b ( Since b=a+1 )

for all the values of a and b.

kogti [31]4 years ago

4 0

If a=-10;then:
a+1=-10+1=-9=b
-9>-10

if a=10; then
a+1=10+1=11=b
11>10
A)The pair of values for a and be are: a=-10, then the value of b would be: -9;
And a=10; then the value of b would be:11;

B) It isn´t possible to create a pair of values for a and be, in wich the numerical relationship shown in the given conditional stament is false, therefore b>a if a+1=b

You might be interested in

The area of Ms. McCarthy’s garden measures 600 square feet. She plants vegetables in 75% of her garden and flowers in the remain

vlabodo [156]

75% is planted with vegetable
so (100-75)% = 25% is planted with flowers
so 25/100 * 600 = 150

Mark brainliest please

5 0

3 years ago

I give branliest to correct <br> How do you solve this equation 4x =100

mafiozo [28]

Answer:

x = 25

Step-by-step explanation:

Since we are trying to multiply 4 by x, we have to divide both sides by 4 to find x.

100 divided by 4 is 25, so x is 25.

To check your answer, we can multiply 4 by 25.

4 × 25 is 100

So, the answer is 25.

3 0

3 years ago

Read 2 more answers

The temperature of a liquid in an experiment is at 0 degrees Celsius at 9 am. The experiment calls for the temperature to drop 1

RSB [31]

Answer:

don't know don't know don't know don't know don't know don't know don't know

Step-by-step explanation:

don't know don't know don't know don't know don't know don't know don't know don't know

8 0

3 years ago

Can someone help me with question e please ?

MAXImum [283]

Answer:

Step-by-step explanation:

a) The domain is R- all real numbers.

b) The domain is R- all real numbers.

c) we need

$x^{2}-4\neq 0\\x^{2} \neq 4\\x\neq 2\\and\\x\neq -2$

So the domain is R\{-2, 2}

we need

$x^{2}+x-2\neq 0\\x\neq 1\\and\\x\neq -2$

So the domain is R\{-2, 1}

we need: x-1>0 or x> 1

So the domain is (1,+∞)

6 0

3 years ago

Graph the function y = 4x4 – 8x2 + 4. Which lists all of the turning points of the graph?

Serhud [2]

Answer:

$4(x + 1)^{2}(x - 1)^{2}$

Step-by-step explanation:

STEP 1:

The equation at the end of step 1

$((4 (x^4)) - 2^3x^2) + 4$

STEP 2:

The equation at the end of step 2:

$(2^2x^4 - 2^3x^2) + 4$

STEP 3:

STEP 4: Pulling out like terms

<u>4.1</u> Pull out like factors:

$4x^4 - 8x^2 + 4 = 4(x^4 - 2x^2 + 1)$

Trying to factor by splitting the middle term

<u>4.2</u> Factoring $x^4 - 2x^2 + 1$

The first term is, $x^4$ its coefficient is 1.

The middle term is, $-2x^2$ its coefficient is -2.

The last term, "the constant", is +1.

Step-1: Multiply the coefficient of the first term by the constant 1 • 1 = 1

Step-2: Find two factors of 1 whose sum equals the coefficient of the middle term, which is -2.

-1 + -1 = -2 That's it

Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -1 and -1

x4 - 1x2 - 1x2 - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

x2 • (x2-1)

Add up the last 2 terms, pulling out common factors :

1 • (x2-1)

Step-5 : Add up the four terms of step 4 :

(x2-1) • (x2-1)

Which is the desired factorization

Trying to factor as a Difference of Squares:

4.3 Factoring: x2-1

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 1 is the square of 1

Check : x2 is the square of x1

Factorization is : (x + 1) • (x - 1)

Trying to factor as a Difference of Squares:

4.4 Factoring: x2 - 1

Check : 1 is the square of 1

Check : x2 is the square of x1

Factorization is : (x + 1) • (x - 1)

Multiplying Exponential Expressions:

4.5 Multiply (x + 1) by (x + 1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x+1) and the exponents are :

1 , as (x+1) is the same number as (x+1)1

and 1 , as (x+1) is the same number as (x+1)1

The product is therefore, (x+1)(1+1) = (x+1)2

Multiplying Exponential Expressions:

4.6 Multiply (x-1) by (x-1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (x-1) and the exponents are :

1 , as (x-1) is the same number as (x-1)1

and 1 , as (x-1) is the same number as (x-1)1

The product is therefore, (x-1)(1+1) = (x-1)2

Final result :

4 • (x + 1)2 • (x - 1)2

4 0

3 years ago

Read 2 more answers