Answer:

Step-by-step explanation:
Let <em>P(A) </em>be the probability that goggle of type A is manufactured
<em>P(B) </em>be the probability that goggle of type B is manufactured
<em>P(E)</em> be the probability that a goggle is returned within 10 days of its purchase.
According to the question,
<em>P(A)</em> = 30%
<em>P(B)</em> = 70%
<em>P(E/A)</em> is the probability that a goggle is returned within 10 days of its purchase given that it was of type A.
P(E/B) is the probability that a goggle is returned within 10 days of its purchase given that it was of type B.
will be the probability that a goggle is of type A and is returned within 10 days of its purchase.
will be the probability that a goggle is of type B and is returned within 10 days of its purchase.





If a goggle is returned within 10 days of its purchase, probability that it was of type B:


So, the required probability is 
The answer is D. <span>transitive property (algebra lesson)
</span>
Answer:
40+32=342
Step-by-step explanation:
Using the commutative of addition change the position of 302 and 40 the expression is 40+302=342 [analysis]
4y=-20+3x and 4y=13.6x-20
so
-20+3x=13.6x-20
3x=13.6x
3=13.6 so it is wrong and system doesn’t have solution