If a + 1 = b, then b > a.
2 answers:
<h2>
Answer with explanation: </h2>
A)
When a is positive:
Let us consider a=10
and a+1=b
This implies that:
b=11
As we know that 11>10
Hence, b>a
When a is negative:
Let us consider a= -2
and a+1=b
This implies that:
b= -1 (Since -2+1= -1 )
As we know that -1 > -2
Hence, b>a
B)
No, it is not possible to create a set of values for a and b such that the numerical relationship shown in the given conditional statement is false .
Since as we no that no matter whether a is positive or negative we always have:
a < a+1
Hence, a< b ( Since b=a+1 )
for all the values of a and b.
If a=-10;then: a+1=-10+1=-9=b -9>-10 if a=10; then a+1=10+1=11=b 11>10 A)The pair of values for a and be are: a=-10, then the value of b would be: -9; And a=10; then the value of b would be:11; B) It isn´t possible to create a pair of values for a and be, in wich the numerical relationship shown in the given conditional stament is false, therefore b>a if a+1=b
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