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iragen [17]
3 years ago
7

What is the value of a 3 - b 2 for a = 3 and b = ? A. 8 B. 8 3/4 26 3/4 26

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
6 0
When b = 1  a^3 - b^2 = 3^3 - 1^2 = 26.
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5 0
3 years ago
Points representing the length if a rectangle are located at A(0,0) and B(8,0). The width of the rectangle is one half its lengt
Anna35 [415]
The length is 8. Therefore, the width is 4.
The area of a rectangle is: 8*4=32 square units. The correct answer is (C)
8 0
3 years ago
Can someone help me on this one please
Paul [167]

Answer:

x=-2

Step-by-step explanation

x+74+37+x+73=180

184+2x=180

-184        -184

2x=-4

x=-2

8 0
2 years ago
A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes
hammer [34]

Answer:

a) The probability that this whole shipment will be​ accepted is 30%.

b) Many of the shipments with this rate of defective aspirin tablets will be rejected.

Step-by-step explanation:

We have a shipment of 3000 aspirin tablets, with a 5% rate of defects.

We select a sample of size 48 and test for defectives.

If more than one aspirin is defective, the batch is rejected.

The amount of defective aspirin tablets X can be modeled as a binomial distribution random variable, with p=0.55 and n=48

We have to calculate the probabilities that X is equal or less than 1: P(X≤1).

P(X\leq1)=P(X=0)+P(X=1)\\\\\\P(0)=\binom{48}{0}(0.05)^0(0.95)^{48}=1*1*0.0853=0.0853\\\\\\P(1)=\binom{48}{1}(0.05)^1(0.95)^{47}=48*0.05*0.0897=0.2154\\\\\\P(X\eq1)=0.0853+0.2154=0.3007

8 0
3 years ago
Find the length of a rectangle with a diagonal of 10 and a height of 8.
Dmitry_Shevchenko [17]

Answer:

The length of the rectangle is 6.

Step-by-step explanation:

Given: The diagonal of a rectangle is 10 and the height is 8.

Please understand, that a diagonal, divides the rectangle into two tringles.

To find the length of the rectangle, you can use Pythagoras on one of the right sided triangles, because the length of the triangle, is also the length of the rectangle!

<em>EXTRA:</em>

<em>If</em><em> you know the special 3 4 5 triangle, a so called Pythagorean Triple, then you can "see" the simularity between the numbers.</em>

<em>Instead of 5, a diagonal of 10 is given (factor of 2 bigger).</em>

<em>Instead of 4, the height of 8 is given (factor of 2 bigger</em><em>)</em><em>.</em><em> </em><em>By scaling the Pythagorean Triple 3 4 5 by a factor of 2, you get the numbers 6 8 10. Could it be, that the number we need to find, is six?</em>

Try to verify, by calculating the missing number (which is the length of the rectangle we are looking for).

a² + b² = c²

a = length (and is unknown)

b = height = 8

c = hypothenusa/diagonal = 10

Substitute the numbers given:

a² + 8² = 10²

Subtract 8² left and right of the = sign.

a² +8² -8² = 10² - 8²

a² + 0 = 100 - 64

a² = 36

a = + - √36

a = + - 6

<em>EXTRA</em><em>:</em>

<em>You</em><em> can ignore the -√36 = -6 part of the solution, because a length of -6 has no meaning here.</em>

a = 6

So, the length of the triangle is 6 and thus, the length of the rectangle is also 6.

8 0
3 years ago
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