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Soloha48 [4]
3 years ago
6

1) express 23kg in miligrams

Chemistry
1 answer:
Semmy [17]3 years ago
5 0
The answer is 23000000 im pretty sure.
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In which part of a plant cell does photosynthesis occur?
IrinaVladis [17]

Answer:

<h2>leaves,</h2>

Hope it helps....⋋✿ ⁰ o ⁰ ✿⋌(・o・)

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3 years ago
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An artifact originally had 16 grams of​ carbon-14 present. the decay model upper a equals 16 e superscript negative 0.000121 ta=
xeze [42]

<u>Given:</u>

Initial amount of carbon, A₀ = 16 g

Decay model = 16exp(-0.000121t)

t = 90769076 years

<u>To determine:</u>

the amount of C-14 after 90769076 years

<u>Explanation:</u>

The radioactive decay model can be expressed as:

A = A₀exp(-kt)

where A = concentration of the radioactive species after time t

A₀ = initial concentration

k = decay constant

Based on the given data :

A = 16 * exp(-0.000121*90769076) = 16(0) = 0

Ans: Based on the decay model there will be no C-14 left after 90769076 years

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3 years ago
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A sample of octane undergoes combustion according to the equation 2 C8H18 + 25 O2 → 16 CO2 + 18 H2O ΔH°rxn = -11018 kJ. What mas
Anna71 [15]

Answer:

\large \boxed{\text{528.7 g} }

Explanation:

It often helps to write the heat as if it were a reactant or a product in the thermochemical equation.

Then you can consider it to be 11018 "moles" of "kJ"  

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r:                      32.00

              2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 8H₂O + 11 018 kJ

n/mol:                                                                  7280

1. Moles of O₂

The molar ratio is 25 mol O₂:11 018 kJ

\text{Moles of O}_{2} = \text{7280 kJ} \times \dfrac{\text{25 mol O}_{2}}{\text{11 018 kJ}} = \text{16.52 mol O}_{2}

2. Mass of O₂

\text{Mass of C$_{8}$H}_{18} = \text{16.52 mol O}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol O}_{2}} = \textbf{528.6 g O}_{2}\\\text{The reaction requires $\large \boxed{\textbf{528.67 g O}_{2}}$}

3 0
3 years ago
Will NaBr, CO2, Ca3(PO4), or KZS raise a liquid's boiling point the most when
Vladimir79 [104]

Answer:

K_2S

Explanation:

According to the boiling point elevation law described by the equation \Delta T_b = iK_bb, the increase in boiling point is directly proportional to the van 't Hoff factor.

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NaBr would produce 2 moles of ions per 1 mole of dissolved substance, sodium and bromide ions.

Ca_3(PO_4)_2 is insoluble in water, so it would barely dissociate and wouldn't practically change the boiling point.

K_2S would dissociate into 3 moles of ions per 1 mole of substance, two potassium cations and one sulfide anion.

CO_2 is a gas, it would form some amount of carbonic acid when dissolved, however, carbonic acid is molecular and would yield i value of i = 1.

Therefore, potassium sulfide would raise a liquid's boiling point the most if all concentrations are equal.

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All of the following will be damaging to the environment except
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Adding fertilizer to stimulate the aquatic plant growth, and putting research and money into renewable energy
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