Answer:
8 × 10³ mol N₂
Explanation:
Step 1: Write the balanced equation
2 C₃H₅N₃O₉ ⇒ 6 CO₂ + 5 H₂O + 0.5 O₂ + 3 N₂
Step 2: Convert the mass of C₃H₅N₃O₉ from tons to grams
We will use the conversion factor 1 t = 907185 g.
1.320 t × 907185 g/1 t = 1.197 × 10⁶ g
Step 3: Calculate the moles corresponding to 1.197 × 10⁶ g of C₃H₅N₃O₉
The molar mass of C₃H₅N₃O₉ is 227 g/mol.
1.197 × 10⁶ g × 1 mol/227 g = 5.27 × 10³ mol
Step 4: Calculate the moles of N₂ formed from 5.27 × 10³ moles of C₃H₅N₃O₉
The molar ratio of C₃H₅N₃O₉ to N₂ is 2:3.
5.27 × 10³ mol C₃H₅N₃O₉ × 3 mol N₂/2 mol C₃H₅N₃O₉ = 7.91 × 10³ mol N₂ ≈ 8 × 10³ mol N₂
The number of pounds present in 2.72 kg of Mastiff puppy is 5.996 pounds
<h3>What is weight?</h3>
Weight can be defined as the gravitation pull on a body. or it can also be defined as the product of the mass of a body and its acceleration due to gravity.
<h3>Units of weight</h3>
weight has several units and they include
- Newton
- pounds
- ounces
- Tons.
These units can be converted.
From the question,
If
But,
Then,
Therefore,
- 2.72 kg of Mastiff = (2720/453.6) pounds of average Mastiff = 5.996 pounds
Hence, The number of pounds present in 2.72 kg of Mastiff puppy is 5.996 pounds.
Learn more about weight here: brainly.com/question/2337612
Wait there was no conclusion abt star Y but since star Z is closest to ear it is more luminous
From the calculations, we can see that, the change in the freezing point is -0.634°C.
<h3>What is freezing point?</h3>
The term freezing point refers to the temperature at which a liquid is changed to solid.
Given that;
ΔT = K m i
Number of moles sucrose = 35.0 g/ 342.30 g/mol = 0.1 moles
molality = 0.1 moles/ 300.0 * 10^-3 Kg
= 0.33 m
Thus;
ΔT = -1.86°C/mol * 0.33 m * 1
= -0.634°C
Learn more about freezing point:brainly.com/question/3121416
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Answer:
156 Hydrogen atoms
Explanation:
<u>Any acyclic alkane has a molecular formula that can be expressed as</u>:
CₙH₂ₙ₊₂
Where <em>n</em> is any integer and the number of carbon atoms. For example, Propane has 3 carbon atoms, this means it would have [2*3+2] 8 hydrogen atoms, resulting with a formula of C₃H₈.
An acyclic alkane with 77 carbon atoms would thus have:
2*77 + 2 = 156 hydrogen atoms
