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Tcecarenko [31]
3 years ago
12

1. If a student needed to calculate the density of irregularly shaped metal beads give a brief explanation of the best way to do

so with a graduated cylinder, water and a balance.2. Using the method described above, calculate the density of a quantity of copper beads. The initial volume of the graduated cylinder with water was 35 ml, the volume of the water plus the beads 40.7 ml and the mass of the beads 50.217 g. What is the density of the beads and what is the percent error.
Chemistry
1 answer:
umka2103 [35]3 years ago
8 0

Answer:

See explanation

Explanation:

The density of an irregular object can be determined using a graduated cylinder, water and a balance as follows.

The irregularly shaped object is weighed in a balance and its mass is recorded. The graduated cylinder is then filled with a given volume of water. This volume of water is also recorded. The irregularly shaped object is then introduced into the graduated cylinder containing the water and the change in volume of the water is recorded.

Volume of the object= change in volume of the water

Density= mass/volume

b)

If the beads weigh 50.217 g

Volume of beads = change in volume of water= 40.7 ml - 35.0ml = 5.7 ml

Density= mass/volume = 50.217 g/5.7 ml = 8.81 g/ml

Accepted value of the density of copper in g/ml = 8.94 g/ml

% error in density = |8.81-8.94|/8.94 ×100

% error in density = 1.45%

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Answer:

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Si se usan 50 gramos de calcio y óxigeno, se obtienen 70 gramos de óxido de calcio.

Explanation:

Hola,

En este caso, la reacción llevada a cabo es:

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mol_{Ca}^{consumidas\ por\ O_2}=50gO_2*\frac{1molO_2}{32gO_2} *\frac{2molCa}{1molO_2} =3.125molCa

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Esto quiere decir que de 50 gramos de oxígeno, solo 20 gramos reaccionan para formar 70 gramos de óxido de calcio.

Saludos!

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