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3 years ago

How many moles of water are produced from 13.35 mol of oxygen?

1 answer:

7 0

In the balanced reaction shown, there are twice as many moles of water as oxygen. If 13.35 moles of oxygen are reacted, 26.70 moles of water is formed

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Which of the following correctly identifies two of the eight elements of weather

Shtirlitz [24]

Are there any options?

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3 years ago

The octet rule states that atoms will gain, lose, or share valence electrons to get a full outer shell (orbital). Explain in you

bezimeni [28]

Answer:

In covalent bonding, the octet rule is important because sharing electrons gives both atoms a full valence shell. As a result, each atom can consider the shared electrons to be part of its own valence shell.

np :)

6 0

2 years ago

Read 2 more answers

A liquid-phase isomerization is carried out in a 1000-gal CSTR that has a single impeller located halfway down the reactor. The

igomit [66]

Answer:

The conversion achieved for the first CSTR impeller is 0.382

Discrepancy = 0.188

Explanation:

The impeller divides the CSTR into 2 equal reactors of volume 500gal

Using V = FaoX/ (-ra)

500gal = Fao×Xa/[(KCao^2( 1 -X1)^2]

500gal = CaoVoX1/ KCao^2(1-X1)

500gal= 500gal × X1'/(1 - X1)^2

(1 -X1)^2 = X1

X1^2 - 3X1 + 1 = 0

X1= 0.382

Conversion achieved in the first CSTR is 0.382

Actual measured CSTR = 57% =57/100=0.57

Discrepancy in the conversions= 0.57 -0.383 =0.188

8 0

3 years ago

Off the top of your head (Mini Quiz) <br><br>What is the chemical composition of Mercury (the metal)

DIA [1.3K]

Symbol: Hg

Made of hydrargyrum

Atomic number: 80

Atomic weight: 200.59

Poor conductor if heat and an ok conductor for electricity. Primarily used for many industrial applications and its salts have been employed therapeutically as purgatives, antisyphilitics, disinfectants, and astringents.

Hope it helps!

4 0

3 years ago

Calculate the solubility (in mol/L) of Fe(OH)3 (Ksp = 4.0 x 10^-38) in each of the following situations:

netineya [11]

Answer:

(A) 1.962x10^-10 M solubility in pure water

(B) 4.0 x 10^-33 M solubility

(C) 4.0 x 10^-27 M solubility

Explanation:

(A) Fe(OH)3 would give (Fe3+) and (3OH-)

Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

Let y = [Fe^3+]

Let 3y = [OH-]

4x10^-38 = (y)(3y)^3

4x10^-38 = 27y^4

y^4 = 4x10^-38 ÷ 27

y^4 = 1.481 x 10^-39

y = 1.962x10^-10 M solubility in pure water

(B) pH = 5.0

5.0 = - log [OH-]

-5.0 = log [OH-]

[OH-] = 10^-5.0 = 1.0 x 10^-5 M

So, Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

[Fe^3+][1.0 x 10^-5] = 4.0 x 10^-38

[Fe^3+] = 4.0 x 10^-38 ÷ 1.0 x 10^-5

= 4.0 x 10^-33 M solubility

11.0 = - log [OH-]

-11.0 = log [OH-]

[OH-] = 10^-11.0 = 1.0 x 10^-11 M

So, Ksp = [Fe^3+][OH-]^3 = 4.0 x 10^-38

[Fe^3+][1.0 x 10^-11] = 4.0 x 10^-38

[Fe^3+] = 4.0 x 10^-38 ÷ 1.0 x 10^-11

= 4.0 x 10^-27 M solubility

6 0

3 years ago