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Black_prince [1.1K]
4 years ago
12

I neeeeeeeeeeeeeeeeeeeed help

Mathematics
2 answers:
Schach [20]4 years ago
6 0
The answer is \frac{1}{4} * 12=3 

Hopes this helps ya 
Nata [24]4 years ago
4 0
1/4 x 12 = 3 . Hope it helps
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Please helppp!!!! will give 5 stars if correct.
Yakvenalex [24]

Answer:

60

Step-by-step explanation:

Because the diameter of this circle is 20 and the formula for the circumference (perimeter) of a circle is pi * the diameter, or πd, which, if π is 3, can be computed as 60.

A takeaway from this problem is that you should memorize basic equations like the circumference/area of a circle.

6 0
3 years ago
Read 2 more answers
PLS HELP ME ON THIS ANSWER I WILL MARK YOU AS BRAINLIEST IF YOU KNOW TGE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!
Vanyuwa [196]

LOL

Answer:

D. The over 30s have a larger range and interquartile range than the under 30s

Step-by-step explanation:

In a data set, the range is the difference between the maximum and minimum. So, the range for under 30s is 20, while the range for over 30s is 24. Additionally, the interquartile range is the difference between Q3 and Q1. For a boxplot, Q3 is the line where the box ends and Q1 is the line where the box begins. Therefore, the IQR for the under 30s is 8, and the IQR for over 30s is 11. So, D must be correct.

4 0
3 years ago
The sum of two numbers is -23, and the difference of the larger and the
geniusboy [140]

The two numbers are 29 and -52

Further explanation:

Let x be the larger number

and

y be the smaller number

then according to given statements

x+y = -23\\x-y=81

Adding both equations

x+y+x-y=-23+81\\2x=58\\\frac{2x}{2} =\frac{58}{2}

x=29

Putting x = 29 in first equation

29+y=-23\\y=-23-29\\y=-52

<u>Proof:</u>

Putting the values of x and y in first equation

29-52=-23\\-23=-23

So, The two numbers are 29 and -52

Keywords: Linear equations in two variables, Elimination method

Learn more about linear equations at:

  • brainly.com/question/6943038
  • brainly.com/question/613883

#LearnwithBrainly

7 0
3 years ago
The area of the rectangular garden shown is 19.5 square meters. How many meters of fencing are needed to go around the​ garden?
Elenna [48]

Answer:

17.66m

Step-by-step explanation:

Let the area of the rectangular garden be L²

A = L²

19.5 = L²

L = √19.5

L = 4.416

Perimeter = 4L

Perimeter = 4(4.416)

Perimeter of the garden =17.66m

Hence the number of meters of fencing that are needed to go around the​ garden is 17.66m

6 0
3 years ago
A normal distribution has mean μ and standard deviation σ .An x-value is randomly selected from the distribution. Find P(μ−σ≤x≤μ
dlinn [17]

Answer:

The probability that a randomly selected  x-value lies between μ − 2σ and μ is the  shaded area under the normal curve shown.  P(μ − 2σ ≤ x ≤ μ) = 0.135 + 0.34 = 0.475

Step-by-step explanation:

5 0
4 years ago
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