If a polynomial P(x) has a zero equal to
a, then (x-a) is a factor of this polynomial. So if a polynomial has zeros
a,
b and
c then it has we could write:
P(x)=(x-a)(x-b)(x-c).
Here we can clearly see that a, making the left hand side 0 because of the factor (x-a), makes the left hand side 0 as well. This means that P(a)=0. This illustrates the discussion above.
Thus, substituting a, b, c with <span>−3, 3, 2 we can write P(x)=(x+3)(x-3)(x-2).
We can expand the right hand side to have the polynomial in standard form:
</span>

We see that all conditions are satisfied.
<span>
Answer: </span>

<span>
</span>