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laiz [17]
3 years ago
11

Sec theta - Csc theta / (csc theta)(sec theta)

Mathematics
2 answers:
Sophie [7]3 years ago
3 0

Answer:

sin(x)-cos(x)

Step-by-step explanation:

\frac{\frac{1}{cos(x)} - \frac{1}{sin(x)}  }{\frac{1}{sin(x)} * \frac{1}{cos(x)}  }

Simplify the denominator:

\frac{\frac{1}{cos(x)} - \frac{1}{sin(x)}  }{\frac{1}{cos(x)sin(x)}  }

Simplify the numerator:

\frac{{\frac{2(sin(x)-cos(x))}{sin(2x)} }  }{\frac{1}{sin(x)} * \frac{1}{cos(x)}  }

Divide the fractions: <u>(a/b)/(c/d) = (a * d)/(b * c)</u>:

\frac{(-cos(x)+sin(x))*2cos(x)sin(x)}{sin(2x)}

Use the identity: <u>2cos(x)sin(x) = sin(2x):</u>

\frac{sin(2x)(-cos(x)+sin(x))}{sin(2x)}

Cancel out the common factor (sin(2x)):

-cos(x) + sin(x)

Simplify:

sin(x) - cos(x)

Afina-wow [57]3 years ago
3 0

Answer:

IDK

Step-by-step explanation:

Sorry this is way too hard.

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The answer would be D
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3 years ago
In a freshman class of 80 students,22 students take Consumer Education,20 students take French,and 4 students take both.Which eq
MAXImum [283]
<h3>Answer: Choice C</h3>

P = 11/40 + 1/4 - 1/20

=========================================================

Explanation:

The formula we use is

P(A or B) = P(A) + P(B) - P(A and B)

In this case,

  • P(A) = 22/80 = 11/40 = probability of picking someone from consumer education
  • P(B) = 20/80 = 1/4 = probability of picking someone taking French
  • P(A and B) = 4/80 = 1/20 = probability of picking someone taking both classes

So,

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 11/40 + 1/4 - 1/20

which is why choice C is the answer

----------------

Note: P(A and B) = 1/20 which is nonzero, so events A and B are not mutually exclusive.

6 0
3 years ago
The radius of the large sphere is times longer than the radius of the small sphere.
jeka94

Answer:

1/3

Step-by-step explanation:

You can try it I keep getting 3 so maybe that’s the answer

8 0
3 years ago
Read 2 more answers
HELP PLEASE 21 POINTS PLEASE HELP ME!!!! &lt;3
Anna007 [38]

1)

n         1          2         3           4         5         6

f(n)    1033    932     831      730     629     528

First term (a₁):  <u>1033 </u>          Common difference (d): <u>-101 </u>

Explicit rule:  a_{n} = 1134 - 101n    Recursive rule: a_{n} = a_{n-1} - 101

a_{n} = a_{1} + d(n - 1)

a_{n} = 1033 - 101(n - 1)

a_{n} = 1033 - 101n + 101

a_{n} = 1134 - 101n

***********************************************************************************

2)

n         1          2         3           4         5         6

f(n)   -39      -29       -19        -9          9        19

First term (a₁):  <u> -39  </u>          Common difference (d): <u> +10  </u>

Explicit rule:  a_{n} = -49 + 10n    Recursive rule: a_{n} = a_{n-1} + 10

a_{n} = a_{1} + d(n - 1)

a_{n} = -39 + 10(n - 1)

a_{n} = -39 + 10n - 10

a_{n} = -49 + 10n

***********************************************************************************

3)

n         1          2         3           4         5         6

f(n)   3.75      2.5     1.25        0      -1.25     -2.5

First term (a₁):  <u> 3.75  </u>          Common difference (d): <u> -1.25  </u>

Explicit rule:  a_{n} = 5 - 1.25n    Recursive rule: a_{n} = a_{n-1} - 1.25

a_{n} = a_{1} + d(n - 1)

a_{n} = 3.75 - 1.25(n - 1)

a_{n} = 3.75 - 1.25n + 1.25

a_{n} = 5 - 1.25n


6 0
3 years ago
Erin gets her exercise by running. The graph shows the distances she covers in a given amount of time. How many hours does it ta
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Answer:

2½ h  

Step-by-step explanation:

Assume the graph is like the one below.

The graph shows how Erin's distance varies with time.

To find out how long it takes Erin to cover 25 mi, find 25 mi on the vertical axis.

From there, draw a horizontal line until it hits the graph.

Then drop a vertical line to the horizontal axis.

It hits half-way between 2 and 3.

It takes Erin 2½ h to run 25 mi.

7 0
3 years ago
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