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Nina [5.8K]
3 years ago
14

A sample of gas has a volume of 125mL at 6.0 atm pressure. What will the new volume in mL be of the pressure is decreased to 0.2

atm?
Chemistry
1 answer:
Rasek [7]3 years ago
3 0
The answer is 607 your welcomeee
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Chalcopyrite is an ore with the composition cufes2. what is the percentage of iron in a 39.6 g sample of this ore? answer in uni
iren2701 [21]
<span>Well it depends on percentage by what, but I'll just assume that it's percentage by mass. For this, we look at the atomic masses of the elements present in the compound. Cu has an atomic mass of 63.546 amu Fe has 55.845 amu and S has 36.065 amu Since there are 2 molecules of Sulfur for each one of Cu and Fe, we'll multiply the Sulfur atomic weight by 2 to obtain 72.13 amu So we have not established the mass of the compound in amus 63.546 + 55.845 + 72.13 = 191.521 That is the atomic mass of Chalcopyrite. and Iron's atomic mass is 55.845 So to get the percentage, or fraction of iron, we take 55.845 / 191.521 Which comes out to 29.15% by mass Mass of the sample is not needed for this calculation, but since the question mentions it I would go ahead and check if the question isn't also asking for the mass of Iron in the sample as well, in which case you just find the 29.15% of 67.7g</span>
5 0
3 years ago
In case of accidental contact with chemicals, how long should the eyes be flushed at the eyewash station
FromTheMoon [43]

Answer:

See the answer below

Explanation:

<em>The duration of flushing the eyes at the eyewash station in case of accidental contact with chemicals depends of the nature of the chemical.</em>

If the chemical is known to be a <u>non-irritant or mild-irritant</u> one, a <u>5-minute </u>washing time is recommended as the first aid. before seeking the help of a physician,

For <u>moderate to severe irritant</u> chemicals, an immediate <u>15-20 minutes</u> washing period is recommended before seeking further medical help.

For <u>corrosive and strong alkalis</u> chemicals, <u>30 and 60 minutes</u> washing are recommended respectively before seeking the attention of a physician.

However, if the nature of the chemical is unknown,<u> a minimum of 20-minutes washing is generally recommended</u> as first aid before seeking immediate medical help.

6 0
3 years ago
How many grams of lead(II) iodide are produced from 6.000 moles of NaI according to the balanced equation: Pb(NO3)2 + 2 NaI à 2
marta [7]

Answer:

mass PbI₂ formed = 1383 grams

Explanation:

Pb(NO₃)₂ + 2NaI => 2NaNO₃ + PbI₂(s)

6 mol NaI =>  1/2(6 mol) PbI₂ = 3 mol PbI₂ x 461.01 g/mol = 1383.03 grams ≅ 1383 grams (4 sig. figs.)

7 0
3 years ago
According to Le Châtelier's principle, what happens if heat is added to a system? apex
anzhelika [568]

Explanation:

Le Chatelier's principle states that for a long period of time if a system is at equilibrium and it is subjected to change in concentration, temperature, volume or pressure then the system shifts to a new equilibrium.

This change will partly counter acts the applied change.

Therefore, when heat is added to the system then equilibrium will shift to the side where temperature or heat is reduced again.

For example,    A + 2B \leftrightharpoons C + D      

Since heat is added to the system, hence, system will shift to the left side or we can say equilibrium will shift to the backward direction.

4 0
4 years ago
Read 2 more answers
Suppose you want to create a 6 ng/μL solution in a 25 mL volumetric flask. However, this concentration cannot really be accurate
Over [174]

Answer:

Mass of chemical = 1.5 mg

Explanation:

Step 1: First calculate the concentration of the stock solution required to make the final solution.

Using C1V1 = C2V2

C1 = concentration of the stock solution; V1 = volume of stock solution; C2 = concentration of final solution; V2 = volume of final solution

C1 = C2V2/V1

C1 = (6 * 25)/ 0.1

C1 = 1500 ng/μL = 1.5 μg/μL

Step 2: Mass of chemical added:

Mass of sample = concentration * volume

Concentration of stock = 1.5 μg/μL; volume of stock = 10 mL = 10^6 μL

Mass of stock = 1.5 μg/μL * 10^6 μL = 1.5 * 10^6 μg = 1.5 mg

Therefore, mass of sample = 1.5 mg

4 0
3 years ago
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