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Nana76 [90]
3 years ago
12

Calculate the volume of an object with a mass of 5.45g and a density of 65

Chemistry
1 answer:
elixir [45]3 years ago
6 0
The answer is 6.10 all together you see its very easy not hard at all you're welcome
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Which compounds are classified as Arrhenius acids?
Olenka [21]

Answer:The correct answer is option 4.

Explanation:

Arrhenius acids are those compounds which gives H^+ ions when dissolved in their aqueous solution.

HA(aq)\rightarrow H^++A^-

Arrhenius bases are those compounds which gives OH^- ions when dissolved in their aqueous solution.

BOH(aq)\rightarrow OH^-+B^+

HBr \& H_2SO_4 are Arrhenius acids because they form H^+ions in their respective aqueous solution.

HBr(aq)\rightarrow H^++Br^-

H_2SO_4(aq)\rightarrow 2H^++SO_{4}^{2-}

Hence, the correct answer is option 4.

6 0
3 years ago
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1. What is a food web?
Anuta_ua [19.1K]

Answer:

a producer and consumer relationship how several food chains and related.

5 0
2 years ago
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Convert 55.6 km to m <br> show equation
crimeas [40]

Explanation:

1 km = 1000m

55.6 km = x m

x = 55.6*1000

x = 55600m

5 0
3 years ago
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how many moles of iron will be produced from 6.20 moles of carbon monoxide reacting with excess iron (III) oxide (FeO3) to produ
Gelneren [198K]

0.20 moles of iron will be formed in the reaction.

Explanation:

The balanced chemical equation for the reaction between iron (iii) oxide and carbon monoxide to form Fe is to be known first.

the balanced reaction is :

Fe2O3 + 3CO⇒ 2 Fe + 3 CO2

so from the data given the number of moles of carbon monoxide can be known:

3 moles of CO reacted with Fe2O3 to form 2 moles of iron in the reaction.

Number of moles of CO is 6.20 moles

11.6 gm of iron is formed

so the number of moles of iron formed is calculated as

n = mass of iron ÷ atomic weight of iron

  = 11.6 ÷ 55.84

  = 0.20 moles of iron will be formed when 11.6 gram of iron is produced.

5 0
3 years ago
What is the formula mass of MgO (how much does one mole of it weigh)
Nadusha1986 [10]

Answer:

40.3044 g/mol

Explanation:

hope this helps

4 0
3 years ago
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