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Kryger [21]
3 years ago
9

License plates are made using 2 letters followed by 3 digits. How many plates can be made if repetition of letters and digits is

allowed? a. 100,000 c. 67,600 b. 676,000 d. 11,881,376 Please select the best answer from the choices provided A B C D
Mathematics
2 answers:
MariettaO [177]3 years ago
5 0

26 x 26 x 10 x 10 x 10 = 676,000 combinations


garik1379 [7]3 years ago
5 0
Its B i just took it.
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See attachment for the whole question.
KengaRu [80]

Using probability concepts, it is found that:

a) \frac{4}{13} probability of drawing a card below a 6.

b) \frac{4}{9} odds of drawing a card below a 6.

c) We should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.

------------------------------

  • A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.

Item a:

  • In a standard deck, there are 52 cards.
  • There are 4 types of cards, each numbered 1 to 13. Thus, 4 \times 5 = 20 are less than 6.

Then:

p = \frac{20}{52} = \frac{4}{13}

\frac{4}{13} probability of drawing a card below a 6.

Item b:

  • Converting from probability to odd, it is:

\frac{4}{13 - 4} = \frac{4}{9}

\frac{4}{9} odds of drawing a card below a 6.

Item c:

  • The law of large numbers states that with a <u>large number of trials, the percentage of each outcome is close to it's theoretical probability.</u>
  • Thus, we should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.

A similar problem is given at brainly.com/question/24233657

7 0
3 years ago
If you paint 1/6 of a fence each day, how many day would it take you to paint 3/4 of the fence?
ololo11 [35]
(3/4) / (1/6)

(3/4) * (6/1) = 18/4 = 4 2/4 = 4 1/2 days
6 0
3 years ago
Read 2 more answers
What is the constant of proportionality equation for this graph?
kodGreya [7K]
Don’t know please help me get an A+
3 0
2 years ago
Read 2 more answers
Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
Rewriting standard form to slope intercept
algol [13]

If you're asking how, here's an example

A standard form equation is when it is set up.

Ax + By = C.

6x + 2y = 4.

A slope-intercept form equation is when it is set up y=mx+b.

Y = - 3x + 2.

4y = -8x + 16 then divide all by 4.

y = -2x + 4 slope form.

3 0
3 years ago
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