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OLga [1]
3 years ago
15

Round 1949.07822364 to the nearest hundred, and please make it the right answer

Mathematics
1 answer:
MaRussiya [10]3 years ago
5 0

the answer is 1900!!!!!!

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The number of cows is given by

14\cdot 2^{\frac{y}{5}}

So, after k years, the number of cows will be

14\cdot 2^{\frac{y+k}{5}}

We want this number to be twice as much as the original:

14\cdot 2^{\frac{y+k}{5}} = 2(14\cdot 2^{\frac{y}{5}})

First of all, we can cancel 14 from both sides:

2^{\frac{y+k}{5}} = 2\cdot 2^{\frac{y}{5}}

Finally, on the right hand side, we can use the exponent rule

a^b\cdot a^c=a^{b+c}

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2^{\frac{y+k}{5}} = 2^{\frac{y}{5}+1}

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\dfrac{y+k}{5} = \dfrac{y}{5}+1 \iff \dfrac{y+k}{5} = \dfrac{y+5}{5}

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You can do the exact same steps to find the doubling time for the sheeps.

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