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3 years ago

Which describes the state at which products form at the same rate as reactants?

2 answers:

swat323 years ago

8 0

Chemical equilibrium is the state in which both reactants and products are present in concentrations which have no further tendency to change with time.
Or, we can say that in chemical equilibrium the ratio between the concentration of the reactants and the products is constant.
Chemical equilibrium is a result state when the forward reaction proceeds at the same rate as the reverse reaction.
Different reactions have different equilibrium.

frosja888 [35]3 years ago

7 0

The correct answer is A

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How do electrons differ from protons and neutrons? A. They do not move. B. They are larger. C. They are not in a fixed position.

nikdorinn [45]

Hi!

Electrons are particles which basically 'orbit' around the nucleus. Protons and neutrons are condensed, in a fixed position inside the nucleus.

With this in mind, the answer will be C.

Hopefully, this helps! =)

4 0

3 years ago

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Sulfur (S) = 32, and of oxygen (O) = 16.

olganol [36]

Answer:

It should be 115.5 amu but you didnt type that as an answer choice so...

Explanation:

Bruh all you had to do was add oxygen and sulfur and subtract from the total to get your answer :D.

5 0

3 years ago

An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective

katovenus [111]

Answer:

The new partial pressures after equilibrium is reestablished:

$PCl_3,p_1'=6.798 Torr$

$Cl_2,p_2'=26.398 Torr$

$PCl_5,p_3'=223.402 Torr$

Explanation:

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At equilibrium before adding chlorine gas:

Partial pressure of the $PCl_3=p_1=13.2 Torr$

Partial pressure of the $Cl_2=p_2=13.2 Torr$

Partial pressure of the $PCl_5=p_3=217.0 Torr$

The expression of an equilibrium constant is given by :

$K_p=\frac{p_1}{p_1\times p_2}$

$=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245$

At equilibrium after adding chlorine gas:

Partial pressure of the $PCl_3=p_1'=13.2 Torr$

Partial pressure of the $Cl_2=p_2'=?$

Partial pressure of the $PCl_5=p_3'=217.0 Torr$

Total pressure of the system = P = 263.0 Torr

$P=p_1'+p_2'+p_3'$

$263.0Torr=13.2 Torr+p_2'+217.0 Torr$

$p_2'=32.8 Torr$

$PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)$

At initail

(13.2) Torr (32.8) Torr (13.2) Torr

At equilbriumm

(13.2-x) Torr (32.8-x) Torr (217.0+x) Torr

$K_p=\frac{p_3'}{p_1'\times p_2'}$

$1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}$

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished:

$p_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr$

$p_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr$

$p_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr$

6 0

3 years ago

An ideal gas is stored in a container at constant volume. If the temperature (T) were increased to 3T, what would be the change

Olin [163]

According to Gayle Lusac's law, pressure is proportional to absolute temperature of a gas. Thus:
P/T = constant

So if the temperature becomes 3T, the pressure would increase to 3P

6 0

3 years ago

Read 2 more answers

Which statement is true?

algol [13]

The statement that is true is that B. Atoms always remain intact during chemical reactions.

Atoms simply mean the basic units of matter. They're the defining structure of an element. Atom is also known as the smallest unit of matter.

It should be noted that atoms always remain intact during chemical reactions. They cannot be added and removed when there are chemical reactions.

Read related link on:

brainly.com/question/19338615

3 0

2 years ago

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