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Mamont248 [21]
3 years ago
10

Transition metals tend to

Chemistry
1 answer:
bonufazy [111]3 years ago
7 0
I think the answer is D all of the above.
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Based on the article, how would you define a heat sink?
tigry1 [53]

Answer:

Glad you know what it is now!

Explanation:

Nice!!

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3 years ago
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Backpackers often use canisters of white gas to fuel a cooking stove’s burner. If one canister contains 1.45 L of white gas, and
rusak2 [61]
1 L ------- 1000 cm³
1.45 L ----- ???

1.45 * 1000 = 1450 cm³  ( volume ) 

Density = 0.710 g/cm³

mass =  in Kg 

m = D * V

m = 0.710  * 1450

m = 1029.5 g

1 Kg ------- 1000 g
   kg -------- 1029.5 g

mass = 1029.5 / 1000

mass = 1.0295 Kg

hope this helps!

7 0
3 years ago
gold has a density of 19.32 g/cm3 if you cut a piece of gold in half how much will the density of each piece be?
Rashid [163]

Answer:

19.32 g/cm³

Explanation:

The density will remain the same no matter how many times you cut the gold.  The density is g/cm³ or g/mL.  Density is essentially how many grams 1 mL of a compound weighs.

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3 years ago
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In chemistry what is nickle (II) nitrate solution mixed with a sodium hydroxide solution
AlladinOne [14]

Answer:

I hope this will help you and Please mark me as Brilliant

Explanation:

Approximately 2 mL of Solution A (on the left) is added to a sample of Solution B (on the right) with a dropping pipet. If a precipitate forms, the resulting precipitate is suspended in the mixture. The mixture is then stirred with a glass stirring rod and the precipitate is allowed to settle for about a minute.

Solution A: 0.5 M sodium hydroxide, colorless

Solution B: 0.2 M nickel(II) nitrate, green

Precipitate: light green

Ni(NO3)2(aq) + 2 NaOH(aq) —> Ni(OH)2(s) + 2 NaNO3(aq)

Credits: 

Design

Kenneth R. Magnell Central Michigan University, Mt. Pleasant, MI 48859

John W. Moore University of Wisconsin - Madison, Madison, WI 53706

Video

Jerrold J. Jacobsen University of Wisconsin - Madison, Madison, WI 53706

Text

Kenneth R. Magnell Central Michigan University, Mt. Pleasant, MI 48859

6 0
3 years ago
If a chemist analyzes a 3.84g sample containing sand and table sugar, and recovers 1.43g of      sand, what  percent by mass of
disa [49]
3.84 - 1.43 = 2.41
2.41g of table sugar

% mass = ( (mass of element) / (total mass) ) * 100
% mass = (2.41 / 3.84) * 100
% mass = (0.6276) * 100
% mass = 62.76

62.76%
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3 years ago
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