Answer:
6.5 seconds
Step-by-step explanation:
Keep in mind that when 
, this is the same height for both when the model rocket takes off and lands, so when the rocket lands, time is positive. Thus:
So, the amount of seconds that the model rocket stayed above the ground since it left the platform is 6.5 seconds
Assume:
Size of sides = x m
Depth of the pool = y m
Therefore, surface area = x^2+4xy =10 m^2
Then, y = (10-x^2)/(4x)
Now,
Volume (V) = x^2*y = x^2*y =x^2(10-x^2)/4x = (10x-x^3)/4 = 1/4(10x-x^3)
For maximum volume, first derivative of volume function is equal to zero.
That is,
dV/dx =0 = 1/4(10-3x^2)
Then,
1/4(10-3x^2) = 0
10-3x^2 = 0
3x^2=10
x= sqrt (10/3) = 1.826 m
And
y= (10-1.826^2)/(4*1.826) = 0.913 m
Therefore,
V= 1.826^2*0.913 = 3.044 m^3
Answer:
6(2) + 6(1) = 18
Step-by-step explanation:
Please show the entire question :)
To solve this one-step equation you:
1. Substract 9 in both sides of the equation:
In this step is the mistake as Sara gets as result -4x=29 and the corret result of substract 9 in both sides of the equation is 5x=20.
2. Divide both sides of the equation into 5:
Then, the answer that Sara should found for the equation is x=4
