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SOVA2 [1]
3 years ago
15

Can someone explain to me the differences between atom vs molecule vs compound vs element with examples? HELPPPPPPPPPPPPPPPPPP

Chemistry
2 answers:
sveta [45]3 years ago
3 0
An element is a substance made from only one type of atom (e.g. oxygen is an element made up of only oxygen atoms).

An atom is the simplest form of an element that can exist, such as a lithium atom (Li).

Atoms of different elements can be combined together to create compounds, e.g sodium oxide (Na2O).

A molecule is a combination of 2 or more atoms that form chemical bonds. When these atoms are of the same element, they can be called molecules (e.g. O3 - ozone).

However when a molecule is made up of atoms of different elements, they are classified as compounds (e.g. CO2 - carbon dioxide).
So all compounds are molecules, but not all molecules are compounds.
mestny [16]3 years ago
3 0
ATOMS are the smallest substances to have unique properties. Everything, all material matter with mass, in the known universe is made up of one or multiple atoms. Each unique atom, with special properties of its own, is referred to as an ELEMENT.

A COMPOUND is 2 or more bonded atoms, even if the same element is bound to itself. These can be ionic and/or covalent bonds (amongst other types).
An example is NaCl sodium chloride, which has an ionic bond.

A MOLECULE is a substance of 2 or more atoms , however, it contains ONLY COVALENT bonds between its atoms. These can be monoatomic (only one atom) or polyatomic (many different elements.
For example, O2 or the oxygen molecule is monoatomic - 2 oxygen atoms covalently bonded.
CO2 or carbon dioxide contains a carbon double covalently bonded to 2 different oxygen atoms.

Every molecule is a compound, but not every compound is a molecule. In other words, molecule is a special subtype of compound.
You might be interested in
Formula New Combination Predicted Formula
creativ13 [48]
Answer:

<span>Formula      New Combination                     Predicted Formula
</span>

NaCl            potassium + chlorine                KCl


AlCl₃             aluminum + fluorine                AlF₃

CO₂              tin + oxygen                              SnO₂

MgCl₂           calcium + bromine                   CaBr₂

HCl               cesium + iodine                       CsI


<span> CCl₄              silicon + bromine                     SiBr₄</span>

Explanation:

1) The question is incomplete. The first part is missing.

This is the first part of the question.

<span>Applying the principle that the elements of a particular column in the Periodic Table share the same chemical properties, complete the following chart. The first one has been done for you.
</span>

2) This is the given chart:

<span>Formula      New Combination                     Predicted Formula
</span>

Cu₂O           silver + oxygen                          Ag₂O   ← this is the example.

NaCl            potassium + chlorine 

<span> AlCl₃             aluminum + fluorine </span>

CO₂              tin + oxygen 

<span> MgCl₂           calcium + bromine </span>

<span> HCl               cesium + iodine </span>

<span> CCl₄              silicon + bromine </span>


3) This is how you find the new formula to complete the chart.

i) NaCl            potassium + chlorine 

Since potassium is in the same group of sodium, you predict that in the new formula Na is replaced by K giving KCl.

ii) AlCl₃             aluminum + fluorine 

Since fluorine is in the same group that Al, then you predict that in the new formula Cl is replaced by F leading to AlF₃

iii) CO₂              tin + oxygen 

Since tin is in the same group that C, you predict that in the new formula C is replaced by Sn leading to SnO₂

iv) MgCl₂           calcium + bromine 

Since calcium is in the same group that Mg, and bromine is in the same group that Cl, you predict thea in the new formula calcium replaces Mg and bromine replaces Cl, leading to CaBr₂

v) HCl               cesium + iodine 

Since H is in the same column that cesium and Cl is in the same colum that iodine, you predict that in the new formula Cs replaces H and I replaces Cl leading to: CsI


<span> vi) CCl₄              silicon + bromine
</span>

Since silicon is in the same column that C and bromine is in the same column that Cl, you predict that in the new formula Si replaces C and Br replaces Cl, leading to SiBr₄
5 0
3 years ago
Eddie and Val observed the picture of an athlete running in a race. Eddie stated the picture shows potential energy being transf
dusya [7]

Answer:

Both Eddie and Val are correct because chemical energy is a type of kinetic energy and mechanical energy includes potential energy.

Explanation:

6 0
4 years ago
Read 2 more answers
The voltage delivered by a primary battery is: _____________
otez555 [7]

Answer:

The voltage delivered by a primary battery is unrelated to its size.

7 0
3 years ago
Some SO2 and O2 are mixed together in a flask at 1100 K in such a way ,that at the instant of mixing, their partial pressures ar
kakasveta [241]

Answer:

The answer is "\bold{0.525\ \ atm^{-1}}"

Explanation:

Given equation:

2SO_2(g) + O_2(g) \leftrightharpoons 2SO_3(g)

Given value:

\Delta rH =-198.2 \ \ \frac{KJ}{mol}

Kp=1100 \ K

\Delta x = 2-(2+1)\\\\

     = 2-(2+1)\\\\= 2-(3)\\\\= -1

\left\begin{array}{cccc}I\ (atm)&1&0.5&0\\C\ (atm)&2x&-x&2x\\E\ (atm)     &1-2x&0.5-x&2x\end{array}\right

calculating the total pressure on equilibrium=  (1-2x)+(0.5-x)+2x \ atm\\\\

                                                                         = 1-2x+0.5-x+2x\\\\= 1+0.5-x\\\\=1.5-x\\

\therefore \\\\\to 1.50-x= 1.35 \\\\\to 1.50-1.35= x\\\\\to 0.15= x\\\\ \to  x= 0.15\\\\

calculating the pressure in  So_2:

= (1-2 \times 0.15)

= 1-0.30 \\\\ =0.70 \ atm

calculating the pressure in  O_2:

= (0.5- 0.15)\\\\= 0.35 \ atm \\

calculating the pressure in  So_3:

= (2 \times 0.15)\\\\= (.30) \ atm \\\\

Calculating the Kp at 1100 K:

= \frac{(Pressure(So_3))^2}{(Pressure(So_2))^2 \times Pressure(O_2)}\\\\= \frac{0.30^2}{0.70^2 \times 0.35}\\\\= \frac{0.30 \times 0.30 }{0.70\times 0.70 \times 0.35}\\\\= \frac{0.09 }{0.49\times 0.35} \\\\= \frac{0.09 }{0.1715} \\\\=  0.5247 \ \  or \ \  0.525 \ \ atm^{-1}  \\\\

4 0
3 years ago
A 64.0 ml volume of 0.25 m hbr is titrated with 0.50 m koh. calculate the ph after addition of 32.0 ml of koh at 25 ∘c.
aleksley [76]
Hello!

The reaction between HBr and KOH is the following:

HBr+KOH→H₂O + KBr

To calculate the amount of HBr left after addition of KOH, you'll use the following equations:

HBr_f=HBr_i-KOH=([HBr]*vHBr)-([KOH]*vKOH) \\  \\ HBr_f=(0,25M*0,64L)-(0,5M*0,32L)=0 mol HBr

That means that after the addition of 32 mL of KOH, there is no HBr left in the solution and the pH should be neutral, close to 7. 

Have a nice day!
3 0
3 years ago
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