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motikmotik
2 years ago
9

Describe how you would find out whether copper(ii) oxide was a catalyst for the decomposition of hydrogen peroxide solution. You

need to show not only that it speeds the reaction up, but that it is chemically unchanged at the end.​
Chemistry
1 answer:
Alik [6]2 years ago
8 0

Answer:

ds

Explanation:

sds

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What is the name for the chemical compound NaBr and is it ionic or covalent
DochEvi [55]

Answer: Sodium bromide is an ionically bonded compound.

(NaBr: Sodium Bromide)

8 0
2 years ago
Which would be an example of a compound?<br> oxygen<br> carbon dioxide<br> sand<br> carbon
GenaCL600 [577]

Answer:

carbondioxide is an example of compound.

4 0
3 years ago
Hibernation is _______. A. An example of an abiotic cycle b. Triggered by changes in the weather c. Caused only by biotic factor
natta225 [31]

The correct answer is option b, that is, triggered by changes in the weather.  

Hibernation refers to a state of lower metabolism and inactivity usually witnessed in endotherms. This condition is featured by a slow heart rate, slow breathing, low metabolic rate, and low body temperature. It assists the majority of the endotherms to thrive in the cold seasons. For example, hibernation of a bear in winters. Therefore, weather change can stimulate hibernation.  


6 0
3 years ago
What is the temperature of 0.5 moles of water vapor that occupies 120 dm3 and applies a pressure of 15,000 Pa to its container?
MArishka [77]
Use the ideal gas law:

PV = nRT

so, T = PV / nR

n=0.5
V= 120 dm^3 = 120 L  (1 dm^3 = 1 L)
R = 1/12
P = 15,000 Pa =  0.147 atm     (1 pa = 9.86 10^{-6} )

Put the values:

T = PV / nR
T = (0.147) (120) / (0.5) (1/12)
T= 426 K
6 0
2 years ago
If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce
Natali5045456 [20]
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over
5 0
3 years ago
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