Answer:
bromine water
Explanation:
a simple test with bromine water can be used to tell the difference between an alkane and an alkene. an alkene will turn brown bromine water colourless as the bromine reacts with the carbon-carbon double bond.
Answer:
The correct answer is sedimintation
7,000 is 100 times larger than 70
Plz mark as brainliest. I rlly need it ;-;
Answer:
The mass of water produced is 59.22 g
Explanation:
This is the balanced equation of methane combustion:
CH₄(g) + 2O₂(g) → CO₂(g) +2H₂O(g)
This equation is balanced because we have the same amount of each element at each side of the equation:
Left side:
CH₄= 1C and 4H
2O₂ = (2x2)O = 4O
Total: 1C, 4H, and 4O
Right side:
CO₂ = 1C and 2O
2H₂O = (2x2)H + (2x1)O = 4H + 2O
Total: 1C, 4H, and 4O
Once it is balanced, we know from the equation that 1 mol of methane (1 CH₄) produces two mols of water ( 2 H₂O) when it reacts with oxygen. The mass of a mol of methane is:
Molar mass CH₄ in grams = mass of the carbon atom + mass of the four H atoms.
Molar mass CH₄ = 12 + 4 = 16 g
The same procedure with water:
Molar mass H₂O in grams = mass of the 2 H atoms + mass of the O atom
Molar mass H₂O in grams = 2 + 16 = 18 g
Hence 16 g (1 mol) CH4 will produce 36 (18 x 2)g H2O.
Therefore:
16 g CH4 ⇒ 36 g H20
26.32 g CH4 ⇒ x= 26.32 * 36 / 16 = <u>59.22 g.</u>
Have a nice day!
