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4 years ago

How many molecules are there in 65 g of silver nitrate (AgNO3)?

Chemistry

1 answer:

Lerok [7]4 years ago

4 0

The correct answer is B, $2.3046 × 10^{23}$

The first step to solving this problem is to find the molar mass of AgN $O_{3}$ . From the periodic table this can be found to be 169.87g/mol. As a reminder, Avogadro's Number tells us that there are 6.022×1 $0^{23}$ molecules per mol.

Now you can set up dimensional analysis to solve the problem as follows:

$65g AgNO_{3} x \frac{1 mol}{169.87g AgNO_{3} } x \frac{6.022x10^{23}molecules }{1 mol}$ ≈ 2.304 $6^{23}$

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Answer:

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3 years ago

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Answer:

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Explanation:

Using Beer-Lambert's law :

Formula used :

$A=\epsilon \times c\times l$

where,

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Now put all the given values in the above formula, we get the molar absorptivity of this solution.

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V = Volume of the solution in L

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3 years ago

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Answer:

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Explanation:

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3 years ago

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