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nekit [7.7K]
4 years ago
5

How many molecules are there in 65 g of silver nitrate (AgNO3)?

Chemistry
1 answer:
Lerok [7]4 years ago
4 0

The correct answer is B, 2.3046 × 10^{23}

The first step to solving this problem is to find the molar mass of AgNO_{3}. From the periodic table this can be found to be 169.87g/mol. As a reminder, Avogadro's Number tells us that there are 6.022×10^{23} molecules per mol.

Now you can set up dimensional analysis to solve the problem as follows:

65g AgNO_{3} x \frac{1 mol}{169.87g AgNO_{3} } x \frac{6.022x10^{23}molecules }{1 mol} ≈ 2.3046^{23}

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Answer:

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To solve this we assume that the hydrogen gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

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<span>V2 = 12.09 L</span>

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4 0
3 years ago
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Answer:

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