Try using Zn (solid) with Cu(NO3)2 in one cell and Cu(s) with Zn(NO3)2 solution in another cell. Note down the voltage value. Ex
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<u>Answer:</u> The mass of allowable in the laboratory is 4599.5 grams
<u>Explanation:</u>
To calculate the volume of cuboid, we use the equation:
where,
V = volume of cuboid
l = length of cuboid = 14 ft
b = breadth of cuboid = 22 ft
h = height of cuboid = 9 ft
Putting values in above equation, we get:
(Conversion factor:
To calculate the moles of gas, we use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 1.00 atm
V = Volume of the gas = 78503.04 L
T = Temperature of the gas =
R = Gas constant =
n = number of moles of hydrogen gas = ?
Putting values in above equation, we get:
Applying unitary method:
For every 109 moles of gas, the moles of present are 1 moles
So, for 3230.4 moles of gas, the moles of present will be =
To calculate the number of moles, we use the equation:
Moles of = 26.94 moles
Molar mass of = 170.73 g/mol
Putting values in above equation, we get:
Hence, the mass of allowable in the laboratory is 4599.5 grams