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Assoli18 [71]
3 years ago
7

Try using Zn (solid) with Cu(NO3)2 in one cell and Cu(s) with Zn(NO3)2 solution in another cell. Note down the voltage value. Ex

plain what you are seeing for voltage value and use redox reaction to justify the process.
Chemistry
1 answer:
miskamm [114]3 years ago
5 0

Answer:

See below

Explanation:

When a strip of zinc metal is placed into a blue solution of copper(II) nitrate, a reaction immediately begins as the zinc strip begins to darken. If left in the solution for a longer period of time, the zinc will gradually decay due to oxidation to zinc ions.

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Explain the difference between oxygen-8 and oxygen-12
kkurt [141]
Here, the number of protons are different. As they have different atomic numbers, it would be: "Isobars"

Hope this helps!
6 0
3 years ago
Which element represents z?
olga nikolaevna [1]

Answer:

Z in chemistry means atomic number but I guess there is 'Zahl'

6 0
3 years ago
Why don’t all of the particles in an atom contribute to the mass?
kotegsom [21]

Answer:

Explanation:

The mass of an atom is dependent on its number of protons and neutrons. Electrons have mass, but are too light in comparison to protons and neutrons to contribute towards the overall mass. Their relative mass is about 1/1840 compared to 1 for protons and neutrons, and therefore are not counted in the mass.

Hope this helped!

4 0
3 years ago
Which chemical equation show a chemical reaction where mass is conserved?
emmainna [20.7K]

Eg: 2H2 + O2 ➡ 2H2O

This shows that sum of reproducts = sum of products.

Therefore, mass is conserved.

I hope this helps you.
7 0
4 years ago
Air in a 0.3-m3 cylinder is initially at a pressure of 10 bar and a temperature of 330 K. The cylinder is to 3 be emptied by ope
FinnZ [79.3K]

Answer:

Explanation:

Since temperature is to be maintained ; constant temperature and a such, the process is ISOTHERMAL

  • T1 = T2 = 330k
  • P1 = 10bar
  • to calculate mass of then gas = P1V/RT1
  • m1 = 10 x 10^5 x 0.3 / 287 x 330
  • = 3.1676kg

  • similarly for m2 = P2V/RT2
  • = 10^5 x 0.3 /287 x 330
  • = 0.31676kg
  • hence required mass = m1 - m2
  • = 2.85kg

b) Considering a well-insulated cylinder ;

Cp = 29J/molK

Temperature T2 = T1 [ P1/P2]^(1-γ)/γ

where γ = 1.4

plugging the values into the equation ; T2 = 171k

hence mass of the gas m1 = P1V/RT1

= 10 x 10^5 x 0.3/287 x 171

= 6.11kg

mass of m2 = P2V/RT2

= 10^5 x 0.3/287 x 171

= 0.611kg

hence required mass = m1 - m2

= 5.50kg

3 0
3 years ago
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