Answer:
21 Moles of Carbon is reacted
Explanation:
According to Balanced Chemical Equation, 2 moles of Hydrogen reacts with 3 moles of Carbon. Hence, for 14 moles of Hydrogen,
= (3 C × 14 H₂) ÷ 2 H₂
= 21 Moles of C
Explanation:
Let the volume of the solution be 100 ml.
As the volume of glycol = 50 = volume of water
Hence, the number of moles of glycol =
=
=
= 0.894 mol
Hence, number of moles of water =
= 2.77
As glycol is dissolved in water.
So, the molality =
= 17.9
Therefore, the expected freezing point =
=
Thus, we can conclude that the expected freezing point is .
Answer:
A: The amount of CaCO₃ decreases.
B: The amount of CaCO₃ increases.
Explanation:
To know how the system will proceed to reach equilibrium, we need to calculate the reaction quotient (Q) and compare it with the equilibrium constant (Kc).
Part A 15.0 g CaCO₃, 15.0 g CaO, and 4.25g CO₂
CaCO₃ and CaO are solids and they do not take part in Q nor Kc, so we will just calculate the concentration of CO₂.
Then,
Q = [CO₂] = 9.66 x 10⁻³
Q < Kc (0.0108), so the reaction will proceed to the right to achieve equilibrium, thus decreasing the amount of CaCO₃.
Part B 2.50 g CaCO₃, 25.0 g CaO, and 5.66g CO₂
Then,
Q = [CO₂] = 0.0129
Q > Kc, so the reaction will proceed to the left to achieve equilibrium, thus increasing the amount of CaCO₃.
Answer :
Explanation : The ideal gas law, states that PV = nRT;
where, P is pressure;
V is volume;
n is number of moles
R is gas constant
T is temperature
If there are two entities to be compared then, it can be compared as,
;
as n and R can be considered as a constant.
Therefore, at constant pressure, the equation will get modified as;