The reaction is 2 NO (g) <----> N2(g) + O2
partial pressures
Initial 37.30 0 0
Change -2p +p +p
Equilibrium 37.30-p p p
Kp = pN2 X pO2 / (pNO)^2
2400 = p^2 / (37.30-p)^2
3339096 - 179040p + 2400p^2 = p^2
2399p^2 + 3339096 -179040 p = 0
On solving
p = 36.55atm
Thus partial pressure of N2 and O2 = 36. 55 atm
Explanation:
It is known that equation for ideal gas is as follows.
PV = nRT
The given data is as follows.
Pressure, P = 1500 psia, Temperature, T = 
= 104 + 460 = 564 R
Volume, V = 2.4 cubic ft, R = 10.73 
Also, we know that number of moles is equal to mass divided by molar mass of the gas.
n = 
m = 
= 
= 9.54 lb
Hence, molecular weight of the gas is 9.54 lb.
- We will calculate the density as follows.
d = 
= 
= 3.975 
- Now, calculate the specific gravity of the gas as follows.
Specific gravity relative to air = 
= 
= 51.96
Answers are:
2. It pushes on all objects that are on Earth’s surface.
3. It can be measured in atmospheres or kilopascals.
Barometric pressure (atmospheric pressure), is the pressure within the atmosphere of Earth
Atmospheric pressure decreases with increasing height, because there are fewer air molecules above a given object.
Barometer is an instrument used in meteorology to measure atmospheric pressure.
Atmospheric pressure (atm) is the force per unit area by the weight of air above that point.
Kilopascal (kPa) is a metric system pressure unit and equals to 1000 force of newton per square meter.
Atmospheric pressure results from molecular collisions of atmospheric gases.
C funnel because the funnel would have a large enough entrance to put a solid through
168.96 g of carbon dioxide (CO₂)
Explanation:
The chemical reaction representing the combustion of acetylene:
2 C₂H₂ (g) + 5 O₂ (g)→ 4 CO₂ (g) + 2 H₂O (g)
number of moles = mass / molecular weight
number of moles of acetylene (C₂H₂) = 50 / 26 = 1.92 moles
Taking in account the stoichiometry of the chemical reaction, we devise the following reasoning:
if 2 moles of acetylene (C₂H₂) produces 4 moles of carbon dioxide (CO₂)
then 1.92 moles of acetylene (C₂H₂) produces X moles of carbon dioxide (CO₂)
X = (1.92 × 4) / 2 = 3.84 moles of carbon dioxide (CO₂)
mass = number of moles × molecular weight
mass of carbon dioxide (CO₂) = 3.84 × 44 = 168.96 g
Learn more about:
combustion of hydrocarbons
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