Missing information:
How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point
Answer:
Step-by-step explanation:
Given
Express the given point P as a unit tangent vector:
Next, find the gradient of P and T using: 
Where
So: the gradient becomes:
![\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]](https://tex.z-dn.net/?f=%5Ctriangle%20T%20%3D%20%5B%28sin%20%5Csqrt%203%29i%20%2B%20%28cos%20%5Csqrt%203%29j%5D%20%2A%20%20%5B%5Cfrac%7B%5Csqrt%203%7D%7B2%7Di%20-%20%5Cfrac%7B1%7D%7B2%7Dj%5D)
By vector multiplication, we have:
Hence, the rate is:
Let
cos x=7/18
x=arc cos (7/18)-----> using a calculator-------> x=67.11°-----> x=1.17 radians
the answer is
x=67.11° or x=1.17 radians
The answer is C because if you look at it carefully C,D, and G are all helping connect the side of the rectangle. Hope it helped!
Linear equations can be written different ways such the form y=mx+b, where m is the slope of the line and b is the y intercept.
We can substitute our given coordinates into the equations to find out which one is correct.
A:
For this equation, when the value of x is - 3, y is 2. This means that A is the correct equation as it passes through the given coordinate (-3,2), and has a slope (m) of 2/3.
