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bogdanovich [222]

3 years ago

12

There are 36 chairs to split evenly between 9 tables. How many chairs will be at each table?

2 answers:

Klio2033 [76]3 years ago

7 0

Hello there.

Question: <span>There are 36 chairs to split evenly between 9 tables. How many chairs will be at each table?

Answer: Divide the number of chairs by the number of tables
36 / 9 = 4.
There would be 4 chairs at each table.

Hope This Helps You!
Good Luck Studying ^-^</span>

8_murik_8 [283]3 years ago

6 0

Your answer would be 4 because 36/9=4 hope this helps

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Given the functions, fx) = x - 8 and g(x) = x2 + x - 1, perform the indicated operation. When applicable, state the domain

adell [148]

Answer:

A

Step-by-step explanation:

(fg)(x) = f(x) × g(x)

= (x - 8)(x² + x - 1)

Each term in the second factor is multiplied by each term in the first factor, that is

x(x² + x - 1) - 8(x² + x - 1) ← distribute both parenthesis

= x³ + x² - x - 8x² - 8x + 8 ← collect like terms

= x³ - 7x² - 9x + 8 → A

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3 years ago

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Ymorist [56]

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3 years ago

What goes into 8 and 18

Lunna [17]

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2 years ago

Read 2 more answers

find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.

DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}$

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}$

Or, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}$

Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 × $\frac{171}{4}$

∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0

3 years ago