Answer:
36s^5
Explanation:
We have;
M2X3 (s)------> 2M^3+(aq) + 3X^2-(aq)
If [M^3+(aq)] = [X^2-(aq)] = s
We then have;
Ksp = (2s)^2 * (3s)^3
Ksp = 4s^2 * 9s^3
Ksp = 36s^5
Note that Ksp is known as the solubility product. It is an equilibrum equation that shows the solubility of a solute in water.
Answer:
the compound contains C, H, and some other element of unknownidentity, so we can’t calculate the empirical formula
Explanation:
Mass of CO2 obtained = 3.14 g
Hence number of moles of CO2 = 3.14g/44.0 g = 0.0714 mol
The mass of the carbon in the sample = 0.0714 mol × 12.0g/mol = 0.857 g
Mass of H2O obtained = 1.29 g
Hence number of moles of H2O = 1.29g/18.0 g = 0.0717 mol
The mass of the carbon in the sample = 0.0717 mol × 1g/mol = 0.0717 g
% by mass of carbon = 0.857/1 ×100 = 85.7 %
% by mass of hydrogen = 0.0717/1 × 100 = 7.17%
Mass of carbon and hydrogen = 85.7 + 7.17 = 92.87 %
Hence, there must be an unidentified element that accounts for (100 - 92.87) = 7.13% of the compound.
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