Answer:
Al(OH)- 4,
Explanation:
NaOH added to 0.010 M Al3+
The predominant species at equilibrium will be = Al(OH)- 4, and this because sodium hydroxide ( NaOH ) is a base will readily form a stable complex ion with aluminum ion like ( Al( OH ) - 4 . also the higher the Kf value the more stable the complex ion becomes and the more soluble Al(OH)3 becomes
hence the predominant species at equilibrium is : Al(OH)- 4,
Answer:
pH = 6.82
Explanation:
To solve this problem we can use the<em> Henderson-Hasselbach equation</em>:
- pH = pKa + log
![\frac{[NaOCl]}{[HOCl]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNaOCl%5D%7D%7B%5BHOCl%5D%7D)
We're given all the required data to <u>calculate the original pH of the buffer before 0.341 mol of HCl are added</u>:
- pKa = -log(Ka) = -log(2.9x10⁻⁸) = 7.54
- [HOCl] = [NaOCl] = 0.500 mol / 0.125 L = 4 M
- pH = 7.54 + log

By adding HCl, w<em>e simultaneously </em><u><em>increase the number of HOCl</em></u><em> and </em><u><em>decrease NaOCl</em></u>:
- pH = 7.54 + log
![\frac{[NaOCl-HCl]}{[HOCl+HCl]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNaOCl-HCl%5D%7D%7B%5BHOCl%2BHCl%5D%7D)
- pH = 7.54 + log

I know that neutrons start nuclear rxns similar to this like Uranium-238. So I am going to say true.
Answer:
15.2L at STP
Explanation:
Given reaction expression;
CaCO₃ → CaO + CO₂
Number of moles of CaCO₃ = 0.68mol
Unknown:
Volume of CO₂ produced at STP = ?
Solution:
To solve this problem, we must first find the number of moles CO₂ produced,
1 mole of CaCO₃ will produce 1 mole of CO₂
0.68mole of CaCO₃ will produce 0.68mole of CO₂ at STP
Now;
1 mole of gas occupies a volume of 22.4L at STP;
0.68mole of CO₂ will then occupy 0.68 x 22.4 = 15.2L at STP
Carbon dioxide (CO₂) it is a molecule with liniar geometry in which the carbon atom is bonded to oxygen atoms by double bonds. Each oxygen will have two lone pairs a electrons that are not involved in the chemical bonds.
Chemical diagram with the lone pairs represented, is found in the attached picture.