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Anestetic [448]
3 years ago
8

Given that the drift mobility of electrons in copper is 32 cm2 V–1 s–1 , and using values of the electrical conductivity, atomic

weight, and density of copper from C&R, compute the number of conduction electrons per atom in copper. (Hint: compute the number of atoms per unit volume in copper, and then compare this to the number of conduction electrons per unit volume (i.e., the carrier density n) computed from copper’s electrical conductivity.) b) In compounds, copper is known to exhibit two common oxidation states, +1 and +2. Discuss whether this fact is consistent with your answer for part a).
Chemistry
1 answer:
vredina [299]3 years ago
3 0
Ggggggggggggggggghhhhhhhhhhhhhhh
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Please help me with this or I may get an F in chemistry :(
umka21 [38]

Answer:

Subconscious - psychic activity just below the level of awareness

Election - the act of electing someone

Explanation:

I hope this helped enough, good luck in chemistry!

8 0
3 years ago
Compared to the nonmetals in Period 2, the metals in Period 2 generally have larger
konstantin123 [22]
The answer is atomic radii; the size or radii of an atom increases from left to right, versus the ionization energies and electronegativities of atoms which increase from right to left.
6 0
3 years ago
in example 5.11 of the text the molar volume of n2 at STP is given as 22.42 L/mol how is this number calculatd how does the mola
Valentin [98]

Answer:

V = 22.42 L/mol

N₂ and H₂ Same molar Volume at STP

Explanation:

Data Given:

molar volume of N₂ at STP = 22.42 L/mol

Calculation of molar volume of N₂ at STP  = ?

Comparison of molar volume of H₂ and N₂ = ?

Solution:

Molar Volume of Gas:

The volume occupied by 1 mole of any gas at standard temperature and pressure and it is always equal to 22.42 L/ mol

Molar volume can be calculated by using ideal gas formula  

                               PV = nRT

Rearrange the equation for Volume

                            V = nRT / P . . . . . . . . . (1)

where

P = pressure

V = Volume

T= Temperature

n = Number of moles

R = ideal gas constant

Standard values

P = 1 atm

T = 273 K

n = 1 mole

R = 0.08206 L.atm / mol. K

Now put the value in formula (1) to calculate volume for 1 mole of N₂

                   V = 1 x 273 K x 0.08206 L.atm / mol. K / 1 atm

                   V = 22.42 L/mol

Now if we look for the above calculation it will be the same for H₂ or any gas. so if we compare the molar volume of 1 mole N₂ and H₂ it will be the same at STP.

6 0
3 years ago
Need help fast please 15 points!!!
In-s [12.5K]

Answer:

C. disposition and condensation ​

Explanation:

8 0
3 years ago
Need help with this.
Jobisdone [24]

Answer:

18.2 g.

Explanation:

You need to first figure out how many moles of nitrogen gas and hydrogen (gas) you have. To do this, use the molar masses of nitrogen gas and hydrogen (gas) on the periodic table. You get the following:

0.535 g. N2 and 1.984 g. H2

Then find out which reactant is the limiting one. In this case, it's N2. The amount of ammonia, then, that would be produced is 2 times the amount of moles of N2. This gives you 1.07 mol, approximately. Then multiply this by the molar mass of ammonia to find your answer of 18.2 g.

5 0
3 years ago
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