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shutvik [7]
2 years ago
11

Best answer will be awarded the brainliest and 5 stars 25+5/2= show your work please

Mathematics
2 answers:
jonny [76]2 years ago
7 0
5/2=2.5
25+2.5=27.5
so 27.5 is the answer
Harlamova29_29 [7]2 years ago
7 0
Okay there are two ways this problem can be approached. The best method I would recommend is to turn the 25 into a like fraction so that we can add them together. So first we are going to place a 2 at the bottom of 25 ------> 25/2. We always have to remember that whatever we do to the bottom we do to the top. So, since we made the bottom a two which is technically an invisible one, we are going to multiply the top (25) by 2 which will give us 50. So now we have 50/2+5/2, which when we add together will give us 55/2. In some cases if we can we will reduce the fraction however in this case we cannot.

Your final answer is 55/2. Hope this helped! :))
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TWO EASY QUESTIONS 8TH GRADE MATH
Sophie [7]
9.
<2 and <6 are right angles by the definition of perpendicular lines.
Since corresponding angles are congruent, m || n.

11.
In a triangle, the measures of the three angles add to 180 degrees.
If one angle is a right angle, then that angle measures 90 degrees. The other two angle measures plus 90 degrees add to 180 degrees, so the other two angle measures add to 90 degrees. In a right triangle there is a right angle and two other angles that are complementary.

Now look at your problem.
One angle is a right angle.
The other two angles are complementary, so their measures add to 90 deg.

8x + 2 + 9x + 3 = 90

17x + 5 = 90

17x = 85

x = 5
3 0
2 years ago
What is the solution to this equation?
kirill [66]
The correct answer for the problem above is -23 .

Explanation

1. collect the like terms

2x + x - 11 + 3 - 7x = 15
2x , x , & -7x are like terms
-11 & 3 are like terms

2x + x -7x = -4x
-11 + 3 = -8

2. Move constant to the right-hand side and change its sign .

-4x = 15 + 8
-4x = 23

3. Make the signs on both sides of the equation

-4x = 23 turning into 4x = -23

answer =

4x = -23



7 0
3 years ago
Sylvia plans to place 617 stamps in an album. Each page of the album holds 5 stamps. She uses division to find out how many full
bija089 [108]

Answer:

123 full pages

Step-by-step explanation:

Given

Total\ Stamps = 617\ stamps

Each\ Page = 5\ stamps

Required

Determine the number of full page

To do this, we simply divide the total stamps by stamps in each page;

Pages = \frac{Total\ Stamps}{Each\ Page}

Pages = \frac{617}{5}

Pages = 123.4

Then we record only the quotient

The quotient is the digits before the decimal

Pages = 123

<em>Hence, she has 123 full pages</em>

8 0
2 years ago
Suppose the diameter of a circle is 4 units. What is its circumference?
Murrr4er [49]
12.5663706144 or yes, 12.57
3 0
3 years ago
Let U1, ..., Un be i.i.d. Unif(0, 1), and X = max(U1, ..., Un). What is the PDF of X? What is EX? Hint: Find the CDF of X first,
Kryger [21]

Answer:

E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}

Step-by-step explanation:

A uniform distribution, "sometimes also known as a rectangular distribution, is a distribution that has constant probability".

We need to take in count that our random variable just take values between 0 and 1 since is uniform distribution (0,1). The maximum of the finite set of elements in (0,1) needs to be present in (0,1).

If we select a value x \in (0,1) we want this:

max(U_1, ....,U_n) \leq x

And we can express this like that:

u_i \leq x for each possible i

We assume that the random variable u_i are independent and P)U_i \leq x) =x from the definition of an uniform random variable between 0 and 1. So we can find the cumulative distribution like this:

P(X \leq x) = P(U_1 \leq 1, ...., U_n \leq x) \prod P(U_i \leq x) =\prod x = x^n

And then cumulative distribution would be expressed like this:

0, x \leq 0

x^n, x \in (0,1)

1, x \geq 1

For each value x\in (0,1) we can find the dendity function like this:

f_X (x) = \frac{d}{dx} F_X (x) = nx^{n-1}

So then we have the pdf defined, and given by:

f_X (x) = n x^{n-1} , x \in (0,1)  and 0 for other case

And now we can find the expected value for the random variable X like this:

E(X) =\int_{0}^1 s f_X (x) dx = \int_{0}^1 x n x^{n-1}

E(X)= n \int_{0}^1 x^n dx = n [\frac{1}{n+1}- \frac{0}{n+1}]=\frac{n}{n+1}

6 0
3 years ago
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