Which of the following is a Riemann Sum used to estimate?

Mathematics

1 answer:

fgiga [73]3 years ago

5 0

Answer:

A. Area under a curve

Step-by-step explanation:

Edge 2021

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How is the quotient of 3,419 and 11 determined using an area model? Enter your answers in the boxes to complete the equations. 3

Ipatiy [6.2K]

The quotient of 3,419 and 11 is 310.81.

<h3>How to illustrate the information?</h3>

It should be noted that from the information given, we are to find the quotient of 3,419 and 11 determined using an area model.

It should be noted that this simply means the division of the values given. This will be:

= 3419/11

= 310.81

Therefore, the quotient of 3,419 and 11 is 310.81.

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1 year ago

Can a triangle be formed with the sides lengths of 8 cm, 5 cm and 13 cm?

Anni [7]

The rule says that the sum of any two sides has to be smaller than the third side so, no it can't

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3 years ago

The population of a city in 2000 was 500,000 while the population of the suburbs of that city in 2000 was 700,000. Suppose that

Mnenie [13.5K]

Answer:

The population of the city in 2002 is 469,280 while the population of the suburb is 730,720.

Step-by-step explanation:

6% of the city's population moves to the suburbs (and 94% stays in the city).
2% of the suburban population moves to the city (and 98% remains in the suburbs).

The migration matrix is given as:

$A= \left \begin{array}{cc} \\ C \\S \end{array} \right\left[ \begin{array}{cc} C&S\\ 0.94&0.06 \\0.02&0.98 \end{array} \right]$

The population in the year 2000 (initial state) is given as:

$\left[ \begin{array}{cc} C&S\\ 500,000&700,000 \end{array} \right]$

Therefore, the population of the city and the suburb in 2002 (two years after) is:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right\left[ \begin{array}{cc} 0.94&0.06 \\0.02&0.98 \end{array} \right]^2$

$A^{2} = \left[ \begin{array}{cc} 0.8848 & 0.1152 \\\\ 0.0384 & 0.9616 \end{array} \right]$

Therefore:

$S_0A^2=\left \begin{array}{cc} [500,000&700,000]\\& \end{array} \right\left \begin{array}{cc} \end{array} \right \left[ \begin{array}{cc} 0.8848 & 0.1152 \\ 0.0384 & 0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 500,000*0.8848+700,000*0.0384& 500,000*0.1152 +700,000*0.9616 \end{array} \right]\\\\=\left[ \begin{array}{cc} 469280& 730720 \end{array} \right]$