A vector is a quantity or phenomenon that has two independent properties: magnitude and direction.
Answer:
position 9.58 m
Explanation:
In impulse exercises and amount of movement, we always assume that the contact time is small,
I = Δp
With this expression we can calculate the final speed
I = m Vf - m Vo
Vf = (I + mVo) / m
Vf = (1.8 + 0.35 1.8) /0.35
Vf = 6.94 m / s
To calculate the acceleration of the ball we use Newton's second law, after finishing the impulse
∑ F = m a
fr = m a
a = fr / m
a = -0.26 / 0.35
a = -0.74 m/s²
A negative sign indicates that this acceleration is slowing the ball
Now we have speed and time acceleration, so we can use the kinematic equations to find the position at 1.5 s
X = Vo t + ½ to t²
In this case Vo is the speed with which the ball comes out after the impulse 6.94
X = 6.94 1.5 + ½ (-0.74) 1.522
X = 9.58 m
Answer:
D bcz the slope rose the fastest
Explanation:
I DON'T WANNA BE QUESTIONED, THIS IS BECAUSE y POSITION ROSE FASTER THAN x POSITION
The total work done of 0.018 joules is needed to move the charges apart and double the distance between them.
We have two electric charges q(A) = 1μc and q(B) = -2μc kept at a distance 0.5 meter apart.
We have to calculate much work is needed to move the charges apart and double the distance between them.
<h3>What s the formula to calculate the Potential Energy of a system of two charges (say 'q' and 'Q') separated by a distance 'r' ?</h3>
The potential energy of the system of two charges separated by a distance is given by -
In order to solve this question, it is important to remember the work - energy theorem which states -
"The change in the energy of the body is equal to work done on it"
Hence, using this work -energy theorem in the question given to us we get -
In our case -
W = 0.018 joules
Hence, the total work done should be 0.018 joules.
To solve more question on potential energy, visit the link below -
brainly.com/question/15014856
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Because the two paths are perpendicular, therefore the
target proton's new path must be at 30 degrees from the original
direction.
Using the law of conservation of momentum about the original direction:
m (400 m/s) = m (v1) cos(60) + m (v2) cos(30)
Cancelling m since the two protons have similar mass.
(v1)cos(60) + (v2)cos(30) = 500 m/s ---> 1
Now by using the law conservation of momentum perpendicular to the original
direction:
m (0 m/s) = m (v1) sin(60) – m (v2) sin(30)
Which simplifies to:
(v1)sin(60) - (v2)sin(30) = 0 m/s
v2 = v1 * sin(60) / sin(30) = v1 * sqrt(3) ---> 2
Plugging equation 2 to equation 1:
(v1) (1/2) + (v1 * sqrt(3)) sqrt(3)/2 = 500 m/s
(1/2) (v1) + (3/2) (v1) = 500 m/s
2 (v1) = 500 m/s
v1 = 250 m/s
Thus, from equation 2:
v2 = v1*sqrt(3) = (250 m/s) sqrt(3) = 433.01 m/s
So,
A. The target proton's speed is about 433 m/s
B. The projectile proton's speed is 250 m/s
