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VashaNatasha [74]
3 years ago
10

One of the largest planes ever to fly, and the largest to fly frequently, is the Ukrainian-built Antonov An-124 Ruslan. The grav

itational potential energy associated with the plane at an altitude of 1450 m is 3,360,000,000 J. What is the airplane's mass?​
Physics
1 answer:
Lerok [7]3 years ago
4 0

Answer:

m = 236212 [kg]

Explanation:

The potential energy can be determined by means of the product of mass by gravity by height. In this way, we have the following equation.

P=m*g*h\\

where:

P = potential energy = 3360000000 [J]

m = mass [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 1450 [m]

Now, we can clear the mass from the equation above:

3360000000=m*9.81*1450\\m = 236212 [kg]

You might be interested in
~~~~~NEED HELP ASAP~~~~~
Romashka-Z-Leto [24]

Answer:

Centripetal Acceleration 18.75 m/s^2, Rotational Kinetic Energy 843.75 J

Explanation:

a Linear acceleration (we cant find tangential acceleration with the givens so we will find centripetal)

a= ω^2*r

ω= 300rev/min

convert into rev/s

300/60= 5rev/s

a= 18.75m/s^2

b) use Krot= 1/2 Iω^2

plug in gives

1/2(30*2.25)(25)= 843.75 J

8 0
2 years ago
Describe the difference between contact forces and field forces.
Salsk061 [2.6K]
Contact forces has to be touching for it to be an actual force. A field force does not have to be touching but it does have to be acting on particles at different positions in a space.
8 0
3 years ago
What is the pressure exerted by an elephant who weighs 2500N and whose feet cover an area of 7.5m2?
qaws [65]

Answer:

0.00339905404

Explanation:

kg: 0.00339905404

pascals: 333.333333

pounds: 0.0483459126

8 0
3 years ago
HELP Please Hurry
nlexa [21]

The correct answers are:

1.

A plane landing on an aircraft carrier.

Rain sticking to a window.

Two train cars coupling together.

2. The total momentum is zero.

3. 3.6 (kg*m/s) (Option C)


Explanations:

1) In simple terms (not a textbook definition), perfectly inelastic collision is a collision in which two bodies stick together (or becomes one) after a collision. Now let us have a look at the options:

<em> A baseball bouncing off a bat</em>: After collision, the ball and the bat do not stick to one another; therefore, it is NOT a perfectly inelastic collision.

<em>Bumper cars bumping off of each other</em>: After collision, cars bump off of each other, making their collision elastic, not perfectly inelastic collision.

<em>A cue ball hitting an eight ball and stopping</em>: After collision, although the cue ball stops, but all of its momentum will be transferred to the eight ball; and eight ball will start moving, where is cue ball stops. Not a perfectly inelastic collision.

<em>A plane landing on an aircraft carrier</em>: After plan lands, the plane and the aircraft carrier will be incontent with each other; making their collision perfectly inelastic.

<em>Rain sticking to a window</em>: Rain drop sticking to a window means both stick together after a collision, making it a perfectly inelastic collision.

<em>Two train cars coupling together</em>: Again both cars are sticking together, making it a perfectly inelastic collision.

Hence the correct answers are:

A plane landing on an aircraft carrier.

Rain sticking to a window.

Two train cars coupling together


7) Always remember that in a closed system, the total momentum is conserved, meaning:

Total initial momentum = Total final momentum


<em>Initially, </em>bodies are <em>at rest</em>, the total initial momentum (mv) is zero (since (m+2m)*0 = 0; as v = 0). <em>As it is the closed system</em>, the total final momentum will be equal to the total initial momentum. As the total initial momentum is zero, the total final momentum will also be zero.

Hence the correct answer is: The total momentum is zero.


3) As you can see in the table, the initial momentum of each and every entry is equal to the final momentum. In the case of X, as the final momentum is 3.6 kg*m/s, the initial momentum will be same as the final momentum (by considering the pattern in the table); therefore X (the initial momentum) will be 3.6 kg*m/s.

Hence the correct answer is: X = 3.6 (Option C)




6 0
3 years ago
Read 2 more answers
A Top Fuel Dragster initially at rest undergoes an average acceleration of 39 m/s2 for 3.97 seconds. How far will it go in this
tigry1 [53]

Answer:

s = 307.34 m

Explanation:

In order to find the distance covered by the dragster during the given time, we will use second equation of motion. The second equation of motion is written as follows:

s = Vi t + (0.5)at²

where,

s = distance covered by the dragster = ?

Vi = Initial Velocity = 0 m/s

t = time interval = 3.97 s

a = acceleration = 39 m/s²

Therefore,

s = (0 m/s)(3.97 s) + (0.5)(39 m/s²)(3.97 s)²

<u>s = 307.34 m</u>

5 0
3 years ago
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