Question

580 nm light shines on a double slit

Answer 1

Answer:

Angular position of the first minimum is 0.27 degree

Explanation:

As we know by the formula of single slit diffraction pattern

$a sin\theta = m\lambda$

here we have

a = d = 0.000125 m

for m = 1

$\lambda = 580 nm$

now we have

$0.000125 sin\theta = 580 \times 10^{-9}$

$sin\theta = 4.64 \times 10^{-3}$

$\theta = 0.27 degree$