Answer:
7.5 m
Explanation:
= initial speed of the ball = 8 m/s
= angle of launch = 40° deg
Consider the motion along the vertical direction :
= initial velocity along vertical direction =
= 8 Sin40 = 5.14 m/s
= acceleration along vertical direction = - 9.8 m/s²
= time of travel
= vertical displacement = - 1 m
Using the kinematics equation
![y = v_{oy}t + (0.5)a_{y}t^{2}](https://tex.z-dn.net/?f=y%20%3D%20v_%7Boy%7Dt%20%2B%20%280.5%29a_%7By%7Dt%5E%7B2%7D)
![- 1 = (5.14)t + (0.5)(- 9.8)t^{2](https://tex.z-dn.net/?f=-%201%20%3D%20%285.14%29t%20%2B%20%280.5%29%28-%209.8%29t%5E%7B2)
= 1.22 sec
Consider the motion along the horizontal direction :
= initial velocity along horizontal direction =
= 8 Cos40 = 6.13 m/s
= acceleration along vertical direction = 0 m/s²
= time of travel = 1.22 sec
= horizontal displacement = ?
Using the kinematics equation
![x = v_{ox}t + (0.5)a_{x}t^{2}](https://tex.z-dn.net/?f=x%20%3D%20v_%7Box%7Dt%20%2B%20%280.5%29a_%7Bx%7Dt%5E%7B2%7D)
![x = (6.13)(1.22) + (0.5)(0)(1.22)^{2](https://tex.z-dn.net/?f=x%20%3D%20%286.13%29%281.22%29%20%2B%20%280.5%29%280%29%281.22%29%5E%7B2)
= 7.5 m
Speed = distance / time
If you input your numbers into this equation you will be able to find the cyclists average speed
Answer:
speed = 7.9 m/s
Explanation:
speed = total distance / time taken
speed = 300 / 38
speed = 7.89473684 m/s
to the nearest tenth
speed = 7.9 m/s
Answer:
Explanation:
Given
mass of box ![m=80 kg](https://tex.z-dn.net/?f=m%3D80%20kg)
coefficient of kinetic friction ![\mu _k=0.15](https://tex.z-dn.net/?f=%5Cmu%20_k%3D0.15)
coefficient of Static friction ![\mu _s=0.30](https://tex.z-dn.net/?f=%5Cmu%20_s%3D0.30)
cart is moving with constant velocity therefore Net Force is zero
Since there is no net acceleration therefore friction force will be zero
mathematically
![f_r=ma](https://tex.z-dn.net/?f=f_r%3Dma)
where ![f_r=frictional\ Force](https://tex.z-dn.net/?f=f_r%3Dfrictional%5C%20Force)
![a=acceleration](https://tex.z-dn.net/?f=a%3Dacceleration)
![a=0](https://tex.z-dn.net/?f=a%3D0)
![f_r=0](https://tex.z-dn.net/?f=f_r%3D0)