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dedylja [7]
3 years ago
9

How do you solve for initial velocity?

Physics
1 answer:
nikdorinn [45]3 years ago
6 0
Velocity is a function of time and defined by both a magnitude and a direction.  Often in physics problems, you will need to calculate the initial velocity (speed and direction) at which an object in question began to travel. There are multiple equations that can be used to determine initial velocity. Using the information given in a problem, you can determine the proper equation to use and easily answer your question. Sorry if this is not what your looking for
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In what way is the structure of the Milky Way galaxy similar to the structure of the solar system?
MissTica
It is the solar system because the planets are in it
4 0
3 years ago
Read 2 more answers
A 1250 kg car starts from rest and speeds up to 14.0 m/s in 7.25s. How much force acted on the car ?
densk [106]
M = 1250 kg
V = 14.0 m/s
t = 7.25 s
F = ?

Impulse equation
F . t = m . V

:. F = mv/t

F = (1250 kg x 14.0 m/s) / 7.25s

F = 2414 N
4 0
4 years ago
Light from a helium-neon laser (λ=633nm) passes through a circular aperture and is observed on a screen 5.80 mm behind the apert
Helga [31]

Explanation:

Whenever the light passes through hole or slit then it tends to bend that is actually a diffraction. It will then made the interference pattern of light and dark bands that due to constructive and destructive interference.

So by using the equation of diffraction,

dsinA = nL

SinA is a geometric component it can be written as,

d\frac{y}{x} = nL

∵ x is the distance from screen.

∵ y is the half of the width of central maximum.

now by putting the values in mm,

d\frac{17}{5.80} = 0.000633

d = 2.15×10^{-4} mm

7 0
3 years ago
¿Cuál será la potencia de una bombilla conectada a una red de energía eléctrica de 440V, si la corriente que circula por el circ
goblinko [34]

Answer:

La potencia de la bombilla es de 1056 W.

Explanation:

La potencia de la bombilla se puede calcular usando la siguiente ecuación:

P = I*V

En donde:

P: es la potencia

I: es la corriente = 2,4 A

V: es la diferencia de potencial = 440 V

Entonces, la potencia es:

P = I*V = 2,4 A*440 V = 1056 W

Por lo tanto, la potencia de la bombilla es de 1056 W.

Espero que te sea de utilidad!

3 0
3 years ago
A 2.3 kg , 20-cm-diameter turntable rotates at 110 rpm on frictionless bearings. Two 460 g blocks fall from above, hit the turnt
boyakko [2]

Answer:

The correct solution is "64 RPM".

Explanation:

The given values are:

Mass,

M = 2.3 kg

Diameter,

D = 20 cm

i.e.,

   = 0.2 m

Rotates at,

N = 110 rpm

Mass of block,

m = 460 g

i.e.,

   = 0.46 kg

According to angular momentum's conservation,

⇒  I_1\omega_1=I_2\omega_2

then,

⇒  I_1=\frac{1}{2}MR_2

On substituting the values, we get

⇒      =\frac{1}{2}\times 2.3\times (0.1)^2

⇒      =\frac{1}{2}\times 0.023

⇒      =0.0115 \ kg \ m^2

Now,

⇒  I_2=I_1+2mR^2

        =0.0115+2\times 0.46\times (0.1)^2

        =0.0115+0.0092

        =0.02 \ kg \ m^2

then,

⇒  0.0115\times 110=0.02\omega_2

⇒              1.265=0.02\omega_2

⇒                  \omega_2=\frac{1.265}{0.02}

⇒                       =63.25 \ or \ 64 \ RPM

7 0
3 years ago
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