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Mazyrski [523]
3 years ago
13

Calculate the binding energy per nucleon of the helium nucleus 52he. express your answer in millions of electron volts to four s

ignificant figures.
Physics
1 answer:
Vitek1552 [10]3 years ago
8 0
The main formula is given by Eb/nucleon = Eb/ mass of nucleid
as for <span>52He, the mass is 5
so by applying Einstein's formula Eb=DmC², Eb=</span><span>binding energy
</span><span>52He-----------> 2 x 11p + 3 x10n is the equation bilan
</span>so Dm=2 mp + (5-2)mn-mnucleus, mp=mass of proton=1.67 10^-27 kg
                                                        mn=mass of neutron=<span>1.67 10^-27 kg
                                                        </span><span>m nucleus= 5
Dm= 2x</span>1.67 10^-27 kg+ 3x<span>1.67 10^-27 kg-5=  - 4.9 J
Eb= </span> - <span>4.9 J x c²= -4.9 x 9 .10^16= - 45 10^16 J
so the answer is Eb /nucleon = Eb/5= -9.10^16 J, but 1eV=1.6 . 10^-19 J
so </span><span>-9.10^16 J/ 1.6 10^-19=  -5.625 10^35 eV

the final answer is </span><span>Eb /nucleon </span><span>=  -5.625 x10^35 eV</span>
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4 years ago
A 4kg watermelon is dropped from a height of 45m. What is the velocity of the watermelon just before it hits the ground?
Makovka662 [10]

Answer:

v=30 m/s

Explanation:

h - height

g - acceleration due to gravity=10

t - time

v- velocity

h =  \frac{1}{2}  \times g \times t {}^{2}

45 = 5t²

t² = 9

t=3 seconds

v=g×t

v=10×3

v=30 m/s

3 0
3 years ago
The froghopper, Philaenus spumarius, holds the world record for insect jumps. When leaping at an angle of 58.0° above the horizo
Norma-Jean [14]

Answer:

0.528m

Explanation:

a)58.7 cm = 0.587 m

Let g = 9.8m/s2. When the frog jumps from ground to the highest point its kinetic energy is converted to potential energy:

E_p = E_k

mgh = mv^2/2

where m is the frog mass and h is the vertical distance traveled, v is the frog velocity at take-off

v^2 = 2gh = 2*9.8*0.587 = 11.5

v = \sqrt{11.5} = 3.4 m/s

b) Vertical and horizontal components of the velocity are

v_v = vsin(\alpha) = 3.4sin(58^0) = 2.877 m/s

v_h = vcos(\alpha) = 3.4cos(58^0) = 1.8 m/s

The time it takes for the vertical speed to reach 0 (highest point) under gravitational acceleration g = -9.8m/s2 is

\Delta t = \Delta v / g = \frac{0 - 2.877}{-9.8} = 0.293s

This is also the time it takes to travel horizontally, we can multiply this with the horizontal speed to get the horizontal distance it travels

s_h = v_ht = 1.8*0.293 = 0.528 m

3 0
3 years ago
Two mirrors are set up at an angle of 90.0°. If light is incident on the first mirror at an angle of 34.6° from the normal, at w
oksano4ka [1.4K]

Answer:

angle of incidence for the second mirror is 55.4 degree  

Explanation:

Given data;

Angle between two mirror is 90 degree

Incident angle on first mirror is 34.6 degree

For first mirror

Angle of incidence  is equal to  angle of reflection

34.6 degree = angle of reflection

r_1 = 42.5 degree

Now , for the triangle ABC         [from figure]

90 - r_1 + 90 + 90 - i_1 = 180

34.6 + i_1 = 90

i_1 = 55.4 degree

The angle of incidence for

angle of incidence for the second mirror is 55.4 degree  

4 0
3 years ago
In the unsaturated zone, the pores of the soil are totally filled with water. T or F
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the answer is clearly false

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3 years ago
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