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Verdich [7]
3 years ago
7

A light plane is headed due south with a speed of 200 km/h relative to still air. After 1.00 hour, the pilot notices that they h

ave covered only 129 km and their direction is not south but 15.0∘ east of south.
(A)What is the wind velocity (magnitude)?

(B)What is the wind velocity (direction)?
Physics
1 answer:
zhannawk [14.2K]3 years ago
7 0

(A)What is the wind velocity (magnitude)

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The barrel of a rifle has a length of 0.855 m. A bullet leaves the muzzle of a rifle with a speed of 553 m/s. What is the accele
Novay_Z [31]

Answer:

Acceleration of the bullet will be 1778835.6 m/sec^2      

Explanation:

We have given length of the barrel refile s= 0.855 m

When the bullet leaves the muzzle its velocity is 553 m/sec

So final velocity v = 553 m/sec

Initial velocity will be 0 that is u = 0 m/sec

According to third equation of motion v^2=u^2+2as

553^2=0^2+2\times a\times 0.855

a=178835.6m/sec^2

5 0
4 years ago
It is found that the most probable speed of molecules in a gas at equilibrium temperature
kaheart [24]

Answer:

\frac{T_2}{T_1} = 1

Explanation:

The root mean square velocity of the gas at an equilibrium temperature is given by the following formula:

v = \sqrt{\frac{3RT}{M} }

where,

v = root mean square velocity of molecules:

R = Universal Gas Constant

T = Equilibrium Temperature

M = Molecular Mass of the Gas

Therefore,

For T = T₁ :

v = \sqrt{\frac{3RT_1}{M} }

For T = T₂ :

v = \sqrt{\frac{3RT_2}{M} }

Since both speeds are given to be equal. Therefore, comparing both equations, we get:

\sqrt{\frac{3RT_1}{M} }=\sqrt{\frac{3RT_2}{M} }\\\\\frac{T_2}{T_1} = 1

8 0
3 years ago
Social loafing is most likely to occur _____.
loris [4]

Answer:

Answer is when no single person in a group is being watched.

Refer below.

Explanation:

Social loafing is most likely to occur:

when no single person in a group is being watched.

5 0
3 years ago
A pump is to lift 18 kg of water per minute tthrough a height of 3.6 m. what output rating (watts) should the pump have?
MrRa [10]
Given: Mass m = 18 Kg;   Height h = 3.6 m;   Time t = 60 s

Required:  Power output  in unit of Watts

Formula: P = mgh/t

               P = (18 Kg)(9.8 m/s²)(3.6 m)/60 s

               P = 10.58 J/s or Watts  


7 0
3 years ago
Viewed from Earth, how does the moon's appearance change during the first week ?
slega [8]
We start to see more off the dark side (waning) or more of the light side (waxing) the more of the dark side we see, the less moon there seems to be. The more light side, the more moon.
6 0
4 years ago
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