<h3>answer</h3>
The minimum velocity required for a object to rotate in a verticle plane is v
1
=
5
gr.
So, at bottom point, T
max
=mv
1
2
/r+mg=6mg.
At top-most point velocity is v
2
=gr.
So, T
min
=mv
2
2
/r−mg=0
So T
max
−T
min
=6mg=2×g⇒m=1/3 kg
Answer:
F = 85696.5 N = 85.69 KN
Explanation:
In this scenario, we apply Newton's Second Law:

where,
F = Upthrust = ?
m = mass of space craft = 5000 kg
g = acceleration due to gravity on surface of Kepler-10b = (1.53)(9.81 m/s²)
g = 15.0093 m/s²
a = acceleration required = 2.13 m/s²
Therefore,

<u>F = 85696.5 N = 85.69 KN</u>
The unit of force is the 'Newton'.
1 newton is the force that accelerates 1 kilogram of mass
at the rate of 1 meter per second-squared.
1 N = 1 kg-m/s²
-- A force of 1 pound is about 4.448 newtons.
-- A force of 1 newton is about 3.6 ounces.
><span>It can travel through vacuum.
The rays must travel in the vacuum of space between Earth's atmosphere and the sun.</span>