To answer this question, it helps enormously if you know 
the formula for momentum:
           Momentum = (mass) x (speed) .
Looking at the formula, you can see that momentum is directly 
proportional to speed.  So if speed doubles, so does momentum.
If the car's momentum is 20,000 kg-m/s now, then after its speed 
doubles, its momentum has also doubled, to 40,000 kg-m/s.
        
                    
             
        
        
        
If they both start from the same height, then they both hit the ground at the 
same time.  It makes no difference if their horizontal speeds aren't equal. 
The cannon ball still accelerates downward at the same rate as the baseball.
        
             
        
        
        
I say around 40% - 60%
https://www.dmv.ca.gov/portal/dmv/detail/teenweb/more_btn6/traffic/traffic
http://www.teendriversource.org/stats/support_teens/detail/57
http://www.rmiia.org/auto/teens/Teen_Driving_Statistics.asp
(I just corrected the question. Sorry if it is still incorrect.)
        
             
        
        
        
It’s D because kinetic energy is the energy of motion
        
                    
             
        
        
        
Answer:
The temperature is  
Explanation:
From the question ewe are told that 
    The rate of heat transferred is    
      The surface area is  
       The emissivity of its surface is  
Generally, the rate of heat transfer is mathematically represented as 
            
=>         ![T  =  \sqrt[4]{\frac{P}{e* \sigma } }](https://tex.z-dn.net/?f=T%20%20%3D%20%20%5Csqrt%5B4%5D%7B%5Cfrac%7BP%7D%7Be%2A%20%5Csigma%20%7D%20%7D)
where   is the Boltzmann constant with value
 is the Boltzmann constant with value  
 substituting value  
              ![T  =  \sqrt[4]{\frac{13.1}{ 0.287* 5.67 *10^{-8} } }](https://tex.z-dn.net/?f=T%20%20%3D%20%20%5Csqrt%5B4%5D%7B%5Cfrac%7B13.1%7D%7B%200.287%2A%205.67%20%2A10%5E%7B-8%7D%20%7D%20%7D)
             