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lyudmila [28]
3 years ago
11

An astronomical telescope has an objective of diameter 20 cm with a focal length of 180 cm. the telescope is used with an eyepie

ce of focal length 30 mm. what is the angular magnification of this telescope?
Physics
1 answer:
Bingel [31]3 years ago
8 0
By definition;
M = fo/fe

Where,
M = Angular magnification
fo = Focal length of objective lens
fe = Focal length of eyepiece lens

From the information given;
M = 180/30 = 6
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B) The movement of the heavy crate is going to the right and in the negative direction on the y-axis

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We need to make a sketch of the different forces acting on the heavy crate.

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Forces in the X-axis

Fdionx=18.5N\\\\Fshix=16.5*cos(30)=14.29N\\Fjoanx=19.5*cos(60)=9.75N\\\\Forcex= 18.5 + 14.29 + 9.75 = 42.54 N

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FDiony=0[N]\\Fshirley= 16.5*sin(30)=8.25[N]\\Fjoany=19.5*sin(60)=16.88 [N]\\\\Forcesy=0+8.25-16.88= -8.63[N]

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Tforce=\sqrt{(42.54)^{2} +(8.63)^{2} } \\\\Tforce= 43.4N

The movement of the heavy crate is going to the right and in the negative direction on the y-axis, this can be easily seen in the graphical sum of vectors.

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