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Sunny_sXe [5.5K]

2 years ago

8

The question is circled I have to find this in degrees from 0-360

1 answer:

Vsevolod [243]2 years ago

6 0

I believe the answer is: -190.98

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Easy Problem just need to make sure I got it right

zloy xaker [14]

Answer:

a

Step-by-step explanation:

We first require the fraction of English to Total

Total = 84 + 38 + 18 + 47 + 69 = 256 , then

$\frac{69}{256}$ × 100% ≈ 27% ( nearest whole number )

5 0

2 years ago

What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve. mc017-1.jpg and x = 1 mc017-2.jpg and x = –1 mc

Wittaler [7]

We are given equation : $x^6+6x^3+5=0$

$Use\:the\:rational\:root\:theorem$

$\mathrm{Therefore,\:we\:need\:to\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:5}{1}$

$-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1$

$\mathrm{Compute\:}\frac{x^6+6x^3+5}{x+1}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }x^5-x^4+x^3+5x^2-5x+5$

Therefore, final factored form it

$x^6\:+\:6x^3\:+\:5=\left(x+1\right)\left(x^5-x^4+x^3+5x^2-5x+5\right)$

We can't factor it more.

Therefore,

x+1=0.

x=-1.

Therefore, the real solution of the equation would be -1.

5 0

3 years ago

Read 2 more answers

How to solve this inequality by graphing

lions [1.4K]

Answer:

Step-by-step explanation:

its all blurry

8 0

2 years ago

Hlol can u plz solve b no plz plz.....I will mark as brainliest

zimovet [89]

Answer:

Step-by-step explanation:

$Tan \ B =\frac{4}{3} = \frac{opposite \ side \ of B}{adjacent \ side \ of B}$

BC = 15 cm

3x = 15

x = 15/3 = 5

AB =4x = 4*5 = 20 cm

Pythagorean theorem,

AC² = AB² + BC²

= 20² + 15 ²

= 400 + 225

= 625

AC = √625 = 25 cm

AC = 25 cm

$Sin \ A = \frac{opposite \ side \ of \ angle A }{hypotenuse}\\\\ = \frac{BC}{AB}=\frac{15}{25}=\frac{3}{5}$

6 0

3 years ago

Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2

nlexa [21]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}$

$\bold{-------------------}$

$\bold{Rewrite}$

$\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Rewrite}$

$\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}$

$\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}$

$\bold{Rewrite}$

$\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}$

$\bold{Simplify}$

$\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

3 0

3 years ago

Read 2 more answers