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3 years ago

PLEASE ANSWER THIS IS EASY BUT IM DUMB LOTS OF POINTS HELP

Mathematics

2 answers:

larisa86 [58]3 years ago

8 0

All three numbers multiplied to get the volume
surface area is the formula times base 1 and base 2 times base 3 and answer

Grace [21]3 years ago

3 0

Ok, first of all, what you have is:
length = 4 m
width = 6 m
height = 5 m

a) For the volume: V = lwh
V = 120 m3
b) For the surface area: S = 2(lw + lh + wh)
S = 148 m2

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In semiconductor manufacturing, wet chemical etching is often used to remove silicon from the backs of wafers prior to metalizat

Viktor [21]

Answer:

Sample mean for solution 1: 19.27; sample mean for solution 2: 10.32

Step-by-step explanation:

To find the sample mean, find the sum of the data values and divide by the sample size.

For solution 1, the sum is given by:

9.7+10.5+9.4+10.6+9.3+10.7+9.6+10.4+10.2+10.5 = 192.7

The sample size is 10; this gives us

192.7/10 = 19.27

For solution 2, the sum is given by:

10.6+10.3+10.3+10.2+10.0+10.7+10.3+10.4+10.1+10.3 = 103.2

The sample size is 10, this gives us

103.2/10 = 10.32

6 0

3 years ago

Rule set for 18250 , 18500 , 19000 , 20000

Rus_ich [418]

I thought doubling everytime except for the number 19000 because if you do 250 × 2 = 500 so then you do 500×2=1000.

3 0

3 years ago

EXPLAIN

zvonat [6]

Answer:

50,000? This is my answer sorry if wrong

Step-by-step explanation:

4 0

2 years ago

Assume that human body temperatures are normally distributed with a mean of 98.22 degrees Upper F 98.22°F and a standard deviati

Anna35 [415]

Answer: 0.00102%

Step-by-step explanation:

Given : Human body temperatures are normally distributed with a mean of $\mu=98^{\circ}F$ and a standard deviation of $s=0.61^{\circ}F$

A hospital uses $100.6^{\circ}F$ as the lowest temperature considered to be a fever.

Let x be the random variable that represents the human body temperatures.

$z=\dfrac{x-\mu}{s}$

For x= 100.6, $z=\dfrac{100.6-98}{0.61}=4.26229508197\approx4.26$

Using normal distribution table for z-values for right-tailed area ,

P(x>100.6)= $P(Z>4.26)=0.0000102=0.00102\%$

Hence, the required probability = 0.00102%

8 0

3 years ago

1 + tanx / 1 + cotx =2

Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer: x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0

3 years ago